(A,) See the figure below. There are two torques applied at B and D. Segment CD is a tube, while AB and BC are solid rods. The cross-sections are shown in the figure, with Ro being the outer radius and Ri the inner radius. AB is made of an aluminum alloy (GaB = 4000 ksi) and BD is made of a steel alloy (Gup = 11000 ksi).

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Problem 1.1MA
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### Instructions from the Figure

The figure below illustrates a mechanical problem involving two applied torques at points B and D on a segmented rod system. The system consists of a composite rod with segments AB, BC, and CD. Here's a detailed understanding of the components and tasks required:

**Material and Structural Details:**

- **Segment AB:** Made of an aluminum alloy with a shear modulus (\(G_{AB}\)) of 4000 ksi. It’s a solid rod with an outer radius of 2 inches.

- **Segment BC:** Made of a steel alloy with a shear modulus (\(G_{BD}\)) of 11,000 ksi. It’s a tube with the outer radius (Ro) of 4 inches and an inner radius (Ri) of 2 inches.

- **Segment CD:** Made of a steel alloy similar to segment BC. It follows the same cross-sectional layout with the same radii.

**Applied Torques:**

- At point B: A torque of 40 lb-ft is applied in a clockwise direction.
- At point D: A torque of 30 lb-ft is applied in a counter-clockwise direction.

**Tasks:**

1. **Determine Internal Torque:**
   - Calculate the internal torque throughout the entire rod system under the influence of the externally applied torques.

2. **Maximum Shear Stress (\(\tau_{max}\)):**
   - Compute the maximum shear stress (\(\tau_{max}\)) in the rod segment between points A and C.
   - Important Notes for Calculation:
     - Explain the reasoning for finding \(\tau_{max}\).
     - Do not calculate shear stress for section CD, as it is not required.

3. **Angle of Twist (\(\theta\)):**
   - Determine the angle of twist (\(\theta\)) of the cross-section at point D relative to the cross-section at point B.
   - Do not calculate the angle of twist for section AB.

### Explanation of the Diagrams

- **Cross-Sectional View:**
  - The cross-sections are visually represented with outlined circular areas.
  - The solid section (AB) and hollow tubular sections (BC and CD) show the relative sizes of the radii.

- **Overall Structural Layout:**
  - It's depicted as a linear rod with defined lengths between points A, B, C, and D:
    - AB: 5 ft
    - BC: 1 ft
    - CD
Transcribed Image Text:### Instructions from the Figure The figure below illustrates a mechanical problem involving two applied torques at points B and D on a segmented rod system. The system consists of a composite rod with segments AB, BC, and CD. Here's a detailed understanding of the components and tasks required: **Material and Structural Details:** - **Segment AB:** Made of an aluminum alloy with a shear modulus (\(G_{AB}\)) of 4000 ksi. It’s a solid rod with an outer radius of 2 inches. - **Segment BC:** Made of a steel alloy with a shear modulus (\(G_{BD}\)) of 11,000 ksi. It’s a tube with the outer radius (Ro) of 4 inches and an inner radius (Ri) of 2 inches. - **Segment CD:** Made of a steel alloy similar to segment BC. It follows the same cross-sectional layout with the same radii. **Applied Torques:** - At point B: A torque of 40 lb-ft is applied in a clockwise direction. - At point D: A torque of 30 lb-ft is applied in a counter-clockwise direction. **Tasks:** 1. **Determine Internal Torque:** - Calculate the internal torque throughout the entire rod system under the influence of the externally applied torques. 2. **Maximum Shear Stress (\(\tau_{max}\)):** - Compute the maximum shear stress (\(\tau_{max}\)) in the rod segment between points A and C. - Important Notes for Calculation: - Explain the reasoning for finding \(\tau_{max}\). - Do not calculate shear stress for section CD, as it is not required. 3. **Angle of Twist (\(\theta\)):** - Determine the angle of twist (\(\theta\)) of the cross-section at point D relative to the cross-section at point B. - Do not calculate the angle of twist for section AB. ### Explanation of the Diagrams - **Cross-Sectional View:** - The cross-sections are visually represented with outlined circular areas. - The solid section (AB) and hollow tubular sections (BC and CD) show the relative sizes of the radii. - **Overall Structural Layout:** - It's depicted as a linear rod with defined lengths between points A, B, C, and D: - AB: 5 ft - BC: 1 ft - CD
Expert Solution
Step 1

In the given problem, the dimensions and Modulus of rigidity have been converted to feet.

Radius, 4in= 0.33ft

Radius, 2in=0.34ft

Modulus of rigidity in BD= 11000=1584000000lb/ft2

The complete solution has been attached.

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