Sex-linked or "X-linked" inheritance Using XG for the normal vision allele and X8 for the color-blind allele, construct the Punnett square that would result from a carrier female (heterozygous = has a normal vision allele on one X chromosome and a color-blind allele on the other X chromosome) mating with a color-blind male (hemizygous recessive = has a color-blind allele on the X chromosome and no allele for vision on the Y chromosome ). Hint: The female genotype is XGX8 and the male genotype is X&Y. The Y chromosome does not have a gene for normal color vision OR color-blind vision b. If they had a son, what are the chances he will be color-blind? c. If they had a daughter, what are the chances she will be color-blind? d. Is there any way these parents might produce a daughter with normal vision? If so, how? e. Is there any chance these parents might produce a son with normal vision? Why or why not?

Sex-linked or "X-linked" inheritance Using XG for the normal vision allele and X8 for the color-blind allele, construct the Punnett square that would result from a carrier female (heterozygous = has a normal vision allele on one X chromosome and a color-blind allele on the other X chromosome) mating with a color-blind male (hemizygous recessive = has a color-blind allele on the X chromosome and no allele for vision on the Y chromosome ). Hint: The female genotype is XGX8 and the male genotype is X&Y. The Y chromosome does not have a gene for normal color vision OR color-blind vision b. If they had a son, what are the chances he will be color-blind? c. If they had a daughter, what are the chances she will be color-blind? d. Is there any way these parents might produce a daughter with normal vision? If so, how? e. Is there any chance these parents might produce a son with normal vision? Why or why not?

Name: Sex-linked or “X-linked” inheritanceUsing XG for the normal vision al
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Description: Sex-linked or “X-linked” inheritanceUsing XG for the normal vision allele and X8 for the color-blind allele, construct the Punnettsquare that would result from a carrier female (heterozygous = has a normal vision allele on one Xchromosome and a colo

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter4: Pedigree Analysis In Human Genetics

Section: Chapter Questions

Problem 17QP: Analysis of X-Linked Dominant and Recessive Traits A young boy is color-blind. His one brother and...

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Concept explainers

Inheritance and Mendelian Genetics

Inheritance means the passing of traits to offspring from parents. These traits could be passed either through asexual reproduction or sexual reproduction. The offspring receives the genetic material from the parents. Mendelian inheritance is a certain biological inheritance that follows the rules and principles laid down by Gregor Mendel in 1865. The initial hypothesis was considered wrong, but other inheritance theories modified the concept of inheritance and thus genetics.

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Question

Sex-linked or “X-linked” inheritance
Using XG for the normal vision allele and X8 for the color-blind allele, construct the Punnett
square that would result from a carrier female (heterozygous = has a normal vision allele on one X
chromosome and a color-blind allele on the other X chromosome) mating with a color-blind male
(hemizygous recessive = has a color-blind allele on the X chromosome and no allele for vision on
the Y chromosome ).
Hint: The female genotype is XGX and the male genotype is X&Y.
The Y chromosome does not have a gene for normal color vision OR color-blind vision
b. If they had a son, what are the chances he will be color-blind?
c. If they had a daughter, what are the chances she will be color-blind?
d. Is there any way these parents might produce a daughter with normal vision? If so, how?
e. Is there any chance these parents might produce a son with normal vision?
Why or why not?

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A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?