Seven subjects are weighed before and after following a particular diet for two months. The average weight loss for the group was -1.6 pounds with a standard deviation of .5 pounds. Using a 0.01 level of significance, test the claim that the diet is effective in reducing weight. a. Write the null and alternative hypotheses to test this claim. b. Perform a t-test for the mean difference from paired or dependent samples. What is the value of the test statistic? c. What is the associated P-value? d. State your conclusion and explain in context using ΅ = 0.05.
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Seven subjects are weighed before and after following a particular diet for two months. The average weight loss for the group was -1.6 pounds with a standard deviation of .5 pounds. Using a 0.01 level of significance, test the claim that the diet is effective in reducing weight.
a. Write the null and alternative hypotheses to test this claim.
b. Perform a t-test for the
c. What is the associated P-value?
d. State your conclusion and explain in context using ΅ = 0.05.
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- The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of 613 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p≠0.5H1: p<0.5B.H0: p=0.5H1: p≠0.5C.H0: p=0.5H1: p<0.5D.H0: p=0.5H1: p>0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? Normal distribution Student (t) distribution χ2Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Right-tailed…The mean potassium content of a popular sports drink is listed as 132 mg in a 32-oz bottle. Analysis of 24 bottles indicates a sample mean of 131.2 mg. (a) State the hypotheses for a two-tailed test of the claimed potassium content.. a. Ho: μ= 132 mg vs. H₁: b. He: ≤132 mg vs. H₁: c. He: ≥132 mg vs. H₁: Oa Ob Oc (b) Assuming a known standard deviation of 2.1 mg, calculate the z test statistic to test the manufacturer's claim. (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.) Test statistic 132 mg >132 mg <132 mg (c) At the 2 percent level of significance (a = .02) does the sample contradict the manufacturer's claim? Decision Rule: Reject Ho
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Perform your hypothesis test, and select the best interpretation of your results from the choices below. Select one: O a. At the 5% level of significance the data are statistically significant. We cannot determine the average family size has decreased since 2010. O b. At the 5% level of significance the data are statisticall significant. We can determine the average family size has decreased since 2010. O c. At the 5% level of significance the data is not statistically significant. We cannot conclude the average family size has decreased since 2010. O d. At the 5% level of significance the data…A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. a. 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The margin of error for a 95% confidence interval for the difference in mean bill color μF – μM (in hue degree) isThe commercial for the new Meat Man Barbecue claims that it takes 9 minutes for assembly. A consumer advocate thinks that the assembly time is higher than 9 minutes. The advocate surveyed 14 randomly selected people who purchased the Meat Man Barbecue and found that their average time was 9.7 minutes. The standard deviation for this survey group was 2.2 minutes. What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use z-test for a population proportion v b. The null and alternative hypotheses would be: Ho: H1: c. The test statistic (t 1.191 (please show your answer to 3 decimal places.) d. The p-value = 0.1169 (Please show your answer to 4 decimal places.) e. The p-value is ? ▼ a f. Based on this, we should | Select an answer the null hypothesis. g. Thus, the final conclusion is that ... 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