Set up integrals for both orders of integration. Use the more convenient order to evaluate the integral over the plane region R. [[x R: sector of a circle in the first quadrant bounded by y = + = 5 13 12 x da 0 12x 5 V 169-x² √169-1² J5y/12 x dy dx x dy dx x dx dy 169x², 12x - 5y = 0, y = 0

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