Show that at least ten of any 64 days chosen must fall on the same day of the week. We prove this using the method of contradiction. This contradiction shows that at least 10 of the days must be on the same day of the week. This would account for at least 10 x 7 = 70 days, but we have chosen only 64 days. Suppose there are nine or fewer days that fall on the same day of the week. Suppose there are 10 or fewer days that fall on the same day of the week. This would account for at most 9 x 7 = 63 days, but we have chosen 64 days.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Show that at least ten of any 64 days chosen must fall on the same day of the week.
We prove this using the method of contradiction.
This contradiction shows that at least 10 of the
days must be on the same day of the week.
This would account for at least 10 x 7 = 70 days,
but we have chosen only 64 days.
Suppose there are nine or fewer days that fall on
the same day of the week.
Suppose there are 10 or fewer days that fall on
the same day of the week.
This would account for at most 9 x 7 = 63 days,
but we have chosen 64 days.
Transcribed Image Text:Show that at least ten of any 64 days chosen must fall on the same day of the week. We prove this using the method of contradiction. This contradiction shows that at least 10 of the days must be on the same day of the week. This would account for at least 10 x 7 = 70 days, but we have chosen only 64 days. Suppose there are nine or fewer days that fall on the same day of the week. Suppose there are 10 or fewer days that fall on the same day of the week. This would account for at most 9 x 7 = 63 days, but we have chosen 64 days.
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