Find the integral. √3x 31 Step 1 8x + 7 1-x² Split the integrand 8x + 7 V 1- x' | 31 J 8x + 7 dx V1-x² 8x + 7 1-x² dx = dx = dx into two parts. 8x √1-x² |- dx + J 1= 1-x² 2x 1 x² dx + -dx 1 V1 = x2 dx | J
Find the integral. √3x 31 Step 1 8x + 7 1-x² Split the integrand 8x + 7 V 1- x' | 31 J 8x + 7 dx V1-x² 8x + 7 1-x² dx = dx = dx into two parts. 8x √1-x² |- dx + J 1= 1-x² 2x 1 x² dx + -dx 1 V1 = x2 dx | J
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Find the integral.**
\[
\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx
\]
**Step 1**
Split the integrand \(\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx\) into two parts.
\[
\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx = \int \frac{8x}{\sqrt{1 - x^2}} \, dx + \int \frac{7}{\sqrt{1 - x^2}} \, dx
\]
\[
\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx = \left(\right) \int \frac{2x}{\sqrt{1 - x^2}} \, dx + \left(\right) \int \frac{1}{\sqrt{1 - x^2}} \, dx
\]
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Transcribed Image Text:**Find the integral.**
\[
\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx
\]
**Step 1**
Split the integrand \(\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx\) into two parts.
\[
\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx = \int \frac{8x}{\sqrt{1 - x^2}} \, dx + \int \frac{7}{\sqrt{1 - x^2}} \, dx
\]
\[
\int \frac{8x + 7}{\sqrt{1 - x^2}} \, dx = \left(\right) \int \frac{2x}{\sqrt{1 - x^2}} \, dx + \left(\right) \int \frac{1}{\sqrt{1 - x^2}} \, dx
\]
**Options:**
- **Submit**
- **Skip (you cannot come back)**
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