Section 18.3.2.3: when is this formula is a maximum with respect to p I(A; x) = -p(1-q)^nlg p+p[1-(1-q)^n]lg [1-(1-q)^n] -[1-p(1-q)^n]lg [1-p(1 q)^n]? We maximize this with respect to p to obtain the covert channel capacity. For notational conveniente, take m= (1 x q)^n and M = (1 x m)^(1-m). Then I(A; X) is a M maximum when p =M/ (Mm+1) So the channel capacity is I(A; X) [Mmlg p+ M(1- m)lg (1 m) + 1g (Mm+1)] / Mm+1 Section 18.3.2.3 derives a formula for I(A; X). Prove that this formula is a maximum with respect to p when p= (M^(1/m))/(1+mM^(1/m))

Section 18.3.2.3: when is this formula is a maximum with respect to p I(A; x) = -p(1-q)^nlg p+p[1-(1-q)^n]lg [1-(1-q)^n] -[1-p(1-q)^n]lg [1-p(1 q)^n]? We maximize this with respect to p to obtain the covert channel capacity. For notational conveniente, take m= (1 x q)^n and M = (1 x m)^(1-m). Then I(A; X) is a M maximum when p =M/ (Mm+1) So the channel capacity is I(A; X) [Mmlg p+ M(1- m)lg (1 m) + 1g (Mm+1)] / Mm+1 Section 18.3.2.3 derives a formula for I(A; X). Prove that this formula is a maximum with respect to p when p= (M^(1/m))/(1+mM^(1/m))

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Section 18.3.2.3:
when is this formula is a maximum with respect to p I(A; X)
-p(1-q)^nlg p+p[1-(1-q)^n]lg [1-(1-q)^n] -[1-p(1-q)^n]lg [1-p(1 - q)^n]?
We maximize this with respect to p to obtain the covert channel capacity. For notational conveniente, take m = (1 x q)^n and M = (1 x m)^(1-m). Then I(A; X) is a M maximum when p =M/(Mm+1).
So the channel capacity is
I(A; X) =
[Mmlg p+ M(1 m)lg (1 - m) + 1g (Mm+1)] / Mm+1
=
Section 18.3.2.3 derives a formula for I(A; X). Prove that this formula is a maximum with respect to p when p = (M^(1/m))/(1+mM^(1/m))

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