Shanks' babystep-giantstep algorithm. Let p-1231. Then g-3 is a primitive root mod p. Let n-36. Let h-642. Let s-3^(-n) mod p. Let list 1 be L1-[1, 3, 3^2. 3^n] (reduced mod p) Let list 2 be L2-[h, h's, h's 2, h's n] (reduced mod p). Find a number on both list 1 and list 2.

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
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Shanks' babystep-giantstep algorithm. Let p=1231.
Then g=3 is a primitive root mod p. Let n-36. Let h-642.
Let s-3^(-n) mod p.
Let list 1 be L1-[1, 3, 3^2, . 3^n] (reduced mod p)
Let list 2 be L2-[h, h's, h's^2, . h's^n] (reduced mod p).
Find a number on both list 1 and list 2.
Transcribed Image Text:Shanks' babystep-giantstep algorithm. Let p=1231. Then g=3 is a primitive root mod p. Let n-36. Let h-642. Let s-3^(-n) mod p. Let list 1 be L1-[1, 3, 3^2, . 3^n] (reduced mod p) Let list 2 be L2-[h, h's, h's^2, . h's^n] (reduced mod p). Find a number on both list 1 and list 2.
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