SECTION 11.4 (More Quantum Formalism*) 11.16 . The Hamiltonian operator is often described as. linear operator because it has the linear property that AH (x) + BH$(x) for 11.2 H[A (x) + B$(x)] = am %3D any two functions (x) and $(x) and any two constant numbers A and B. Prove that the one-dimensional Hamiltonian (11.11) is linear. 11.17. Show that the wave functions (11.21) for the infi- nite square well satisfy the orthogonality property that m(x)*\n(x) dx = 0 for m + n. %3D SECTION 115 (T Section 11.4 More Quantum Formalism 339 nensional system for now.) The form dy as a differential equation, but it is not the form in which the equation is normally written in more advanced work, where it is ctric usually reorganized to read onal h? d? + U(x) \µ = Ep 2m dx? %3D (11.10) The quantity in the square brackets on the left is a differential operator, or just Thetor: "Operating" on a function , it gives the function -(k²/2m) 99 Or " + Uy. This operator is so important, it is given a name, the Hamiltonian operator, or just Hamiltonian, * and is denoted H f h2 d? + U(x) (11.11) %3D 2m dx2 The Hamiltonian is intimately connected to the energy of the system. For example, if is the plane wave y = e'kx (11.12) = [K+ U] + U 2m %3D h? d? %3D + U \eikx Hy = 2m dx² times giver (K U)
SECTION 11.4 (More Quantum Formalism*) 11.16 . The Hamiltonian operator is often described as. linear operator because it has the linear property that AH (x) + BH$(x) for 11.2 H[A (x) + B$(x)] = am %3D any two functions (x) and $(x) and any two constant numbers A and B. Prove that the one-dimensional Hamiltonian (11.11) is linear. 11.17. Show that the wave functions (11.21) for the infi- nite square well satisfy the orthogonality property that m(x)*\n(x) dx = 0 for m + n. %3D SECTION 115 (T Section 11.4 More Quantum Formalism 339 nensional system for now.) The form dy as a differential equation, but it is not the form in which the equation is normally written in more advanced work, where it is ctric usually reorganized to read onal h? d? + U(x) \µ = Ep 2m dx? %3D (11.10) The quantity in the square brackets on the left is a differential operator, or just Thetor: "Operating" on a function , it gives the function -(k²/2m) 99 Or " + Uy. This operator is so important, it is given a name, the Hamiltonian operator, or just Hamiltonian, * and is denoted H f h2 d? + U(x) (11.11) %3D 2m dx2 The Hamiltonian is intimately connected to the energy of the system. For example, if is the plane wave y = e'kx (11.12) = [K+ U] + U 2m %3D h? d? %3D + U \eikx Hy = 2m dx² times giver (K U)
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How might I be able to prove that the Hamiltonian is linear in Problem 11.16? This problem is in a chapter called "Atomic transitions and Radiation." The chapter is under
![SECTION 11.4 (More Quantum Formalism*)
11.16 . The Hamiltonian operator is often described as.
linear operator because it has the linear property that
AH (x) + BH$(x) for
11.2
H[A (x) + B$(x)] =
am
%3D
any
two functions (x) and $(x) and any two constant
numbers A and B. Prove that the one-dimensional
Hamiltonian (11.11) is linear.
11.17. Show that the wave functions (11.21) for the infi-
nite square well satisfy the orthogonality property
that m(x)*\n(x) dx = 0 for m + n.
%3D
SECTION 115 (T](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81ed2a7d-ef58-4ac0-a29f-af1e2992bb8e%2Fccdf0f63-4ebe-4923-a5c6-10edb8c1c45b%2Flarmcxa.jpeg&w=3840&q=75)
Transcribed Image Text:SECTION 11.4 (More Quantum Formalism*)
11.16 . The Hamiltonian operator is often described as.
linear operator because it has the linear property that
AH (x) + BH$(x) for
11.2
H[A (x) + B$(x)] =
am
%3D
any
two functions (x) and $(x) and any two constant
numbers A and B. Prove that the one-dimensional
Hamiltonian (11.11) is linear.
11.17. Show that the wave functions (11.21) for the infi-
nite square well satisfy the orthogonality property
that m(x)*\n(x) dx = 0 for m + n.
%3D
SECTION 115 (T
![Section 11.4 More Quantum Formalism 339
nensional system for now.) The form
dy as a differential equation, but it is not the form in
which the equation is normally written in more advanced work, where it is
ctric
usually reorganized to read
onal
h? d?
+ U(x) \µ = Ep
2m dx?
%3D
(11.10)
The quantity in the square brackets on the left is a differential operator, or just
Thetor: "Operating" on a function , it gives the function -(k²/2m)
99
Or
" + Uy. This operator is so important, it is given a name, the Hamiltonian
operator, or just Hamiltonian, * and is denoted H
f
h2 d?
+ U(x)
(11.11)
%3D
2m dx2
The Hamiltonian is intimately connected to the energy of the system. For
example, if is the plane wave y = e'kx
(11.12)
= [K+ U]
+ U
2m
%3D
h? d?
%3D
+ U \eikx
Hy =
2m dx²
times
giver (K U)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81ed2a7d-ef58-4ac0-a29f-af1e2992bb8e%2Fccdf0f63-4ebe-4923-a5c6-10edb8c1c45b%2F5eewq55.jpeg&w=3840&q=75)
Transcribed Image Text:Section 11.4 More Quantum Formalism 339
nensional system for now.) The form
dy as a differential equation, but it is not the form in
which the equation is normally written in more advanced work, where it is
ctric
usually reorganized to read
onal
h? d?
+ U(x) \µ = Ep
2m dx?
%3D
(11.10)
The quantity in the square brackets on the left is a differential operator, or just
Thetor: "Operating" on a function , it gives the function -(k²/2m)
99
Or
" + Uy. This operator is so important, it is given a name, the Hamiltonian
operator, or just Hamiltonian, * and is denoted H
f
h2 d?
+ U(x)
(11.11)
%3D
2m dx2
The Hamiltonian is intimately connected to the energy of the system. For
example, if is the plane wave y = e'kx
(11.12)
= [K+ U]
+ U
2m
%3D
h? d?
%3D
+ U \eikx
Hy =
2m dx²
times
giver (K U)
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