PROBLEMS FOR CHAPTER 11 SECTION 11.2 (Radiation by Classical Charges) with de dE deentined frem Find dr di wbeer ( crude approximation that dr estimate roughly bow leng thie alet in from 7 m lor (F mate, see Prolem 11.15) 11.7 Many particle acceleraters and the synchrotrun (Sections charged partacles in a circulas at magnetic Seld The centrpetal accela can be very large and can lead o by radiation, in accordance with E sader a 10-MeV proton in a cyclotron.o Use the formuda (11.11 to calculate te Inss in Vs chue to radiotion. (b) Sopan tried to prodace electrons with the sam gy in a circular machine of the sa Case the motH M t berelativat a (111 odified by an estra ta f 11.1 A charge q executes simple hamonic motion with po- silionr- A sin aa (a) Find P. the total power of the adiation ensitted by this oscallating charge (b) Show that the average power over one complete cycle is (P) = 34 11.2 In the antenna of a TV or radio station, charges os- cillate al some frequency / and radiate electromag netic waves of the same frequency As a simple model of such an antenna, imagine that a single charge q-250 nC is executing simple harmonic motion at 100 MH with amplhtude 3 m. (1 aC- 10 cuulomb) Ue the result of Problem 11.1 to cakulate the average total power radiated by this antenna. 3A certain oell phone transmitter radiates 3 W of power a abot 900 MH (a) Find the rate of emas on of photons by the transmitter (b) In this case is there an appreciable diflerence between the correct quantum view and the classical picture un which the radialion is emited continunuslr 114 Carry out the calulation of Example 11.1 sing St tnit throughou No vou use a calulator and ex ed its axium expent range (usally It you hid caloulato the mantissa and ejnent separately] The formula (11.1) for the power Prahated by an lerating charge e can be derived by the method dimendonal analysis Since Pwould be expected to and we might reasonahly gisa thal Fed the rabe of emergy lass of thie elostmon pare with that fra prut oer er troa shoult be enormoly larger than e th This explains why mnt clectvn aclo var, not carcular since the apceleramem in a celeratoresce e a Tas s centripetal acerleration oomdure bes 11.8 Answet the same qto alsue that oth the groesn aes enotgy 10 CieVand move i (ta this cane oib partcles ane m Use the relativs formala 11.9 The rig lled PE S stoys clectroas wbelng Staticcharge distribution (Sec 113 sorption of a phet /ssion uf a plt DETAILS P2kq'a'/ (11.1) shd bave the form Lidetime- 10 (114) whate in sne dimepstonlen eumbet of der bapa omehine liku đ and whers (11 48

PROBLEMS FOR CHAPTER 11 SECTION 11.2 (Radiation by Classical Charges) with de dE deentined frem Find dr di wbeer ( crude approximation that dr estimate roughly bow leng thie alet in from 7 m lor (F mate, see Prolem 11.15) 11.7 Many particle acceleraters and the synchrotrun (Sections charged partacles in a circulas at magnetic Seld The centrpetal accela can be very large and can lead o by radiation, in accordance with E sader a 10-MeV proton in a cyclotron.o Use the formuda (11.11 to calculate te Inss in Vs chue to radiotion. (b) Sopan tried to prodace electrons with the sam gy in a circular machine of the sa Case the motH M t berelativat a (111 odified by an estra ta f 11.1 A charge q executes simple hamonic motion with po- silionr- A sin aa (a) Find P. the total power of the adiation ensitted by this oscallating charge (b) Show that the average power over one complete cycle is (P) = 34 11.2 In the antenna of a TV or radio station, charges os- cillate al some frequency / and radiate electromag netic waves of the same frequency As a simple model of such an antenna, imagine that a single charge q-250 nC is executing simple harmonic motion at 100 MH with amplhtude 3 m. (1 aC- 10 cuulomb) Ue the result of Problem 11.1 to cakulate the average total power radiated by this antenna. 3A certain oell phone transmitter radiates 3 W of power a abot 900 MH (a) Find the rate of emas on of photons by the transmitter (b) In this case is there an appreciable diflerence between the correct quantum view and the classical picture un which the radialion is emited continunuslr 114 Carry out the calulation of Example 11.1 sing St tnit throughou No vou use a calulator and ex ed its axium expent range (usally It you hid caloulato the mantissa and ejnent separately] The formula (11.1) for the power Prahated by an lerating charge e can be derived by the method dimendonal analysis Since Pwould be expected to and we might reasonahly gisa thal Fed the rabe of emergy lass of thie elostmon pare with that fra prut oer er troa shoult be enormoly larger than e th This explains why mnt clectvn aclo var, not carcular since the apceleramem in a celeratoresce e a Tas s centripetal acerleration oomdure bes 11.8 Answet the same qto alsue that oth the groesn aes enotgy 10 CieVand move i (ta this cane oib partcles ane m Use the relativs formala 11.9 The rig lled PE S stoys clectroas wbelng Staticcharge distribution (Sec 113 sorption of a phet /ssion uf a plt DETAILS P2kq'a'/ (11.1) shd bave the form Lidetime- 10 (114) whate in sne dimepstonlen eumbet of der bapa omehine liku đ and whers (11 48