V.6.* 001111Use the technology display to make a decision to reject or fail to reject the null hypothesis at a=0.05. Make the decision using thestandardized test statistic and using the P-value. Assume the sample sizes are equal.1111Click the icon to view the technology display.1.1111Choose the correct answer below.LL11O A. Reject the null hypothesis because the P-value is greater than the level of significance.50OB. Fail to reject the null hypothesis because the P-value is greater than the level of significance.O C. Fail to reject the null hypothesis because the P-value is less than the level of significance.O D. Reject the null hypothesis because the P-value is less than the level of significance.Next12:47PM61°F Sunny罗@v1202/E2/14查 0+.F12PrtScF10F11F5.9.8.H.K.

# In a given hypothesis testing conclude the result based on the comparison of pvalue and level of significance ,alpha=0.05 ??

Answered: se the technology display to make a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Did I calculate this correctly? Thank you.
What is the null and alternative hypothesis for the following problem? Thank you
In a Gallup poll of 1003 randomly selected subjects, 370 said they have a gun in their home. The accompanying Minitab display shows the results from a test at the 0.05 significance level of the claim that 40% of homes have guns in them. a. Explain the meaning of the p-value in the context of the problem.
Please see picture. Need this asap please and thank you.
Maps YouTube PeopleForms Contr... → Morning Song by S... e Morning Song The... How smallpox deva... G Atzec cared about s... Test the claim that the mean GPA of night students is larger than 2.7 at the 0.005 significance level. The null and alternative hypothesis would be: Ho:p> 2.7 Ho: p=0.675 Ho: p 0.675 Ho: 0.675 H₁: p2.7 H₁: 2.7 O of O O O The test is: two-tailed left-tailed right-tailed O Based on a sample of 55 people, the sample mean GPA was 2.73 with a standard deviation of 0.02 The p-value is: Based on this we: O Reject the null hypothesis Fail to reject the null hypothesis Question Help: Video Post to forum Submit Question (to 2 decimals)
In 1970, 590 students among 1000 randomly selected college freshmen thought that capital punishment should be abolished. In 2005, 350 students among 1000 randomly selected college freshmen thought that capital punishment should be abolished. What is the two-sample z test statistic for evaluating the null hypothesis that the percentage of students who support capital punishment did not change from 1970 to 2005? Round your answer to two decimal places.
2. The steps of hypothesis testing You intend to draw a random sample in order to test a hypothesis about an unknown population mean. You will use a hypothesis test. A description of each of the steps of a hypothesis test follows, but they may be specified in the incorrect order. Specify the correct order of the steps. Determine the null and alternative hypotheses. Select a level of significance. Make a decision about the unknown population. Select a sample and compute the z-score for the sample mean.
If you use a 0.025 level of significance in a (two-tail) hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean is 600 if you use the Z test? Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING... Question content area bottom Part 1 Which of the following decision rules is correct? A. Reject H0 if ZSTAT<−2.24 or ZSTAT>+2.24. B. Reject H0 if −2.24<ZSTAT<+2.24. C. Reject H0 if −1.96<ZSTAT<+1.96. D. Reject H0 if ZSTAT<−1.96 or ZSTAT>+1.96.
The mean price of mid-sized cars in a region is $57,600. A test is conducted to see if the claim is true. Identify the null hypothesis. ? v? v Identify the alternative hypothesis. ? v:?v| ? v Identify the type I error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not $57,600. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is nor $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is $57,600. Identify the type II error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not…
Use the random sample data to test the claim that 72% of students have internet access at home. Use 5% level of significance. Sample data: x = 158, n = 200 1. Identify the tail of the test. 2.Find the P-value 3.Will the null hypothesis be rejected? 4. Is the initial claim supported?
Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is u = 16.00 Mbps. The sample size is n = 20 and the test statistic is t = 1.776.
A hospital has a main campus and three satellite locations. Management wants to reduce waiting time for ER cases. A random sample of 11 ER cases at each location was selected, and the waiting time was measured. Excel.) Complete parts (a) through (d) to determine if there is statistical evidence of a difference in the mean waiting times betweeen the four locations. a. State the two hypotheses. Choose the correct answer below. O B. Ho: H1 = H2 = ••• = H4 H;: 41 H2# • • • # µ4 O A. Ho: H1 =H2 = ••• = H4 H;: Not all H are equal (where j= 1,2,.4) OC. Họ: H1 = H2 = • •• = H1 H;: 41 # H2# • •• #H11 D. Ho: H1 = H2= • •• - H11 H;: Not all H; are equal (where j= 1,2,.,11) b. At the 0.05 level of significance, state the test statistic. (Round to two decimal places to the right of the decimal point as needed.) O A. FSTAT = 0.005 , from the first row of the ANOVA table O B. FSTAT = 4.91 , from the first row of the ANOVA table O C. FSTAT = 2.05 , from the first row of the ANOVA table O D. FSTAT =…

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