Use the technology display to make a decision to reject or fail to reject the null hypothesis at a = 0.05. Make the decision using the standardized test statistic and using the P-value. Assume the sample sizes are equal.Click the icon to view the technology display.Choose the correct answer below.OA. Reject the null hypothesis because the P-value is greater than the level of significance.OB. Fail to reject the null hypothesis because the P-value is greater than the level of significance.OC. Fail to reject the null hypothesis because the P-value is less than the level of significance.OD. Reject the null hypothesis because the P-value is less than the level of significance.- XTechnology Output2-SampZTestp12Z-0.948424933p 0.3429131714x1-2400x2-2320n1-100PrintDone

Given:Standardized test statistic 𝑧=0.9484249P-value 𝑝=0.342913Comparing the p-value to…

Answered: Use the technology display to make a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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sanjay
1. Make a statistical decision about the null. Will you reject or fail to reject the null based on your sample data? 2. Justify your decision regarding the null. 3. Calculate the effect size for the comparison of those who estimated the line while alone vs. those who estimated in the length of line B when others told them it was 7 inches long (using Cohen's d). How large of an effect size is this (small, medium, or large)?
Claim more than 25% of a class is majoring into Nursing (or Nursing-BSN). Test at the 0.5 significance level. Complete the full hypotheses test answering all the questions here. You can use the traditional or p- value method. Sort out the data. 1. What type of test will need to be used? 2. What is the sample size, n, for major? How many business (including business management) majors, X? Use "=counta" instead of "=count" to count qualitative data 3. Hypothesis test . . • Hypotheses • Ho Ha Critical value* ← Test Value (or p-value) Decision *Skip if your using the p-value method. Summary/conclusion 4. Is there a possible type I or type II error? 5. What can you conclude about business majors from this hypothesis test?
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
q11
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Assume that you plan to use a significance level of a= 0.05 to test the claim that p1 = p2 . Use the given sample sizes and numbers of successes to find the P-value for the hypothesis test. n1 = 50 x1 = 8 n2 = 50 x2 = 7
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A company claims that its packages of 100 candies are distributed with the following color percentages: 15% red, 21% orange, 12% yellow, 14% brown, 24% blue, and 14% green. Use the given sample data to test the claim that the color distribution is as claimed. Use a 0.025 significance level. E Click the icon to view the color counts for the candy in the package. Click here to view the chi-square distribution table. The test statistic is (Round to two decimal places as needed.) The critical value is (Round to three decimal places as needed.) State the conclusion. Ho. There sufficient evidence to warrant rejection of the claim that the color distribution is as claimed. Candy Package Counts Candy Counts Number in Package Color Red 14 Orange 23 Yellow 10 Brown 7 Blue 27 Green 19 Enter vOur C newer in ooe
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A company claims that its packages of 100 candies are distributed with the following color percentages: 14% red, 21% orange, 14% yellow, 11% brown, 24% blue, and 16% green. Use the given sample data to test the claim that the color distribution is as claimed. Use a 0.025 significance level. Click the icon to view the color counts for the candy in the package. Click here to view the chi-square distribution table. Į The test statistic is (Round to two decimal places as needed.) The critical value is (Round to three decimal places as needed.) State the conclusion. Ho. There ▼ sufficient evidence to warrant rejection of the claim that the color distribution is as claimed. C Candy Package Counts Color Red Orange Yellow Brown Blue Green Candy Counts Number in Package 14 Print 25 6 9 27 19 Done X
Perform a hypothesis test to determine whether there is a difference in the mean attendance of teams between the two groups created in Part F. Use a 0.05 level of significance in your testing procedures. Hint: When calculating your pooled sample variance and your test statistic, assume the Top 10 data is sample 1 and the Bottom 10 data is sample 2. Decision Rule -t < or t > = REJECT H0 Value of Pooled Sample Variances Value of test statistic Decision: enter Reject or Do Not Reject Is there a difference in the mean attendance between the two groups assuming a 0.05 level of significance? Enter Yes or No. Another variable that can impact attendance is the team's win-loss record. Teams that are winning more games are thought to have increased attendance as fans prefer to see their home team "win" rather than "lose" (although for some teams such as the Chicago Cubs, this is not always an established relationship!). Create 2 samples…
The October 2019 Gallup Poll reported the proportion of Republicans, Independents, and Democrats who favor the legalization of marijuana. Here are the results: Step 1: Test Set-Up Step 2. Select the Level of Significance, α A 5 percent significance level is selected. Step 3. State the Null Hypothesis (H0) and Alternate Hypothesis (H1) H0: H1: Step 4. Compose the Decision Rule Step 5. Calculate the Value of the Test Statistic, p-value, and estimate statistical power (Use G*Power) Use G*Power to calculate statistical power. Use these settings: Test family: z tests Statistical test: Proportion: Difference between two independent proportions Type of power analysis: Post hoc: Compute achieved power – given α, sample size and effect size Step 6. Decide and Report
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