se a a = 0.05 level of significance, find or compute the critical value of F. (Round nitical value of F is

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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a-2. Use a a = 0.05 level of significance, find or compute the critical value of F. (Round your answer to 2 decimal places.)
The critical value of F is
b. Using the ttest from Chapter 11, compute t. (Negative amount should be indicated by a minus sign. Round your answer to 3
decimal places.)
c. There is any difference in the mean test scores.
Ho. There is
in the mean scores between lecture and distance-based formats.
Transcribed Image Text:a-2. Use a a = 0.05 level of significance, find or compute the critical value of F. (Round your answer to 2 decimal places.) The critical value of F is b. Using the ttest from Chapter 11, compute t. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) c. There is any difference in the mean test scores. Ho. There is in the mean scores between lecture and distance-based formats.
When only two treatments are involved, ANOVA and the Student's t-test (Chapter 11) result in the same conclusions. Also, for computed
test statistics, t = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a
history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The
other group of eight students took the course as a distance course format. At the end of the course, each group was examined with a
50-item test. The following is a list of the number correct for each of the two groups.
Traditional Lecture
Distance
32
47
31
32
40
44
31
31
34
43
37
34
46
43
picture Click here for the Excel Data File.
a-1. Complete the ANOVA table. (Round your SS, MS, and Fvalues to 2 decimal places and p-value and Fcrit to 4 decimal places.)
Source of Variation
SS
df
MS
p-value
F crit
Treatment
Error
Total
Transcribed Image Text:When only two treatments are involved, ANOVA and the Student's t-test (Chapter 11) result in the same conclusions. Also, for computed test statistics, t = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The other group of eight students took the course as a distance course format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each of the two groups. Traditional Lecture Distance 32 47 31 32 40 44 31 31 34 43 37 34 46 43 picture Click here for the Excel Data File. a-1. Complete the ANOVA table. (Round your SS, MS, and Fvalues to 2 decimal places and p-value and Fcrit to 4 decimal places.) Source of Variation SS df MS p-value F crit Treatment Error Total
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