Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.14 days to watch the entire first season of a television series, with a standard deviation of 4.03 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample z-test, with significance level of a = 0.05, to test the null hypothesis, Ho: µ = 6.14 days, against the alternative hypothesis, H1: µ < 6.14 days. The variable µ is the mean amount of time, in days, that it takes for customers to watch the first season of a television series. Scarlett selects a simple random sample of 825 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table. Sample Sample Standard size mean error n SE 825 5.84 0.1403
Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.14 days to watch the entire first season of a television series, with a standard deviation of 4.03 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample z-test, with significance level of a = 0.05, to test the null hypothesis, Ho: µ = 6.14 days, against the alternative hypothesis, H1: µ < 6.14 days. The variable µ is the mean amount of time, in days, that it takes for customers to watch the first season of a television series. Scarlett selects a simple random sample of 825 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table. Sample Sample Standard size mean error n SE 825 5.84 0.1403
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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![Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.14 days to watch the entire first season of a television series, with a standard deviation of 4.03 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample z-test, with significance level of \(\alpha = 0.05\), to test the null hypothesis, \(H_0: \mu = 6.14\) days, against the alternative hypothesis, \(H_1: \mu < 6.14\) days. The variable \(\mu\) is the mean amount of time, in days, that it takes for customers to watch the first season of a television series.
Scarlett selects a simple random sample of 825 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table.
\[
\begin{array}{|c|c|c|}
\hline
\text{Sample size} & \text{Sample mean} & \text{Standard error} \\
n & \bar{x} & \text{SE} \\
\hline
825 & 5.84 & 0.1403 \\
\hline
\end{array}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c9732cb-ae4a-4d93-bf70-995c53334240%2F61c3e50b-7ee5-433d-8f01-a1b2a32c03a1%2F0r2wp8a_processed.png&w=3840&q=75)
Transcribed Image Text:Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.14 days to watch the entire first season of a television series, with a standard deviation of 4.03 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample z-test, with significance level of \(\alpha = 0.05\), to test the null hypothesis, \(H_0: \mu = 6.14\) days, against the alternative hypothesis, \(H_1: \mu < 6.14\) days. The variable \(\mu\) is the mean amount of time, in days, that it takes for customers to watch the first season of a television series.
Scarlett selects a simple random sample of 825 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table.
\[
\begin{array}{|c|c|c|}
\hline
\text{Sample size} & \text{Sample mean} & \text{Standard error} \\
n & \bar{x} & \text{SE} \\
\hline
825 & 5.84 & 0.1403 \\
\hline
\end{array}
\]
![**Instruction:**
Compute the *P*-value for Scarlett's hypothesis test directly using a normalcdf function on a TI calculator or by using software. You may find some software manuals helpful. Provide your answer with precision to four decimal places. Avoid rounding until the final step.
**Input Box:**
- **P-value =** [Text box]
- **Status:** Incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c9732cb-ae4a-4d93-bf70-995c53334240%2F61c3e50b-7ee5-433d-8f01-a1b2a32c03a1%2Fvhqkgng_processed.png&w=3840&q=75)
Transcribed Image Text:**Instruction:**
Compute the *P*-value for Scarlett's hypothesis test directly using a normalcdf function on a TI calculator or by using software. You may find some software manuals helpful. Provide your answer with precision to four decimal places. Avoid rounding until the final step.
**Input Box:**
- **P-value =** [Text box]
- **Status:** Incorrect
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