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(a) Do the data in the table present sufficient evidence to indicate a difference in the average prices of light tuna in water versus oil? Test using a = 0.05. State the null and alternative hypotheses. O Ho: (H₁-H₂) = 0 versus H₂: (H₁-H₂) <0 O Ho: (H₁-H₂) < 0 versus H₂: (μ₁ −µ₂) > 0 Ho: (H₁-H₂) = 0 versus H₂: (H₁-H₂) = 0 O Ho: (H₁-H₂) = 0 versus H₂: (μ₁ −μ₂) = 0 O Ho: (H₁-H₂) = 0 versus H₂: (H₁-H₂) >0 State the test statistic. t= State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three places.)

(a) Do the data in the table present sufficient evidence to indicate a difference in the average prices of light tuna in water versus oil? Test using a = 0.05. State the null and alternative hypotheses. O Ho: (H₁-H₂) = 0 versus H₂: (H₁-H₂) <0 O Ho: (H₁-H₂) < 0 versus H₂: (μ₁ −µ₂) > 0 Ho: (H₁-H₂) = 0 versus H₂: (H₁-H₂) = 0 O Ho: (H₁-H₂) = 0 versus H₂: (μ₁ −μ₂) = 0 O Ho: (H₁-H₂) = 0 versus H₂: (H₁-H₂) >0 State the test statistic. t= State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three places.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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I need help with all parts of this queestion 6, the select options for C is greater thna or less than, and is or is not

(a) Do the data in the table present sufficient evidence to indicate a difference in the average prices of light tuna in water versus oil? Test using a = 0.05. State the null and alternative hypotheses. O Ho: (M₁M₂) = 0 versus H₂: (M₁ - H₂) <0 O Ho: (M₁M₂) < 0 versus H₂: (M₁-M₂) >0 O Ho: (M₁M₂) = 0 versus H₂: (μ₁ −μ₂) # 0 O Ho: (M₁M₂) 0 versus H₂: (μ₁ −μ₂) = 0 O Ho: (M₁M₂) = 0 versus H₂: (M₁M₂) >0 State the test statistic. t = State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three places.) t> State the conclusion. O Ho is rejected. There is insufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. O Ho is not rejected. There is sufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. O Ho is not rejected. There is insufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. O Ho is rejected. There is sufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. (b) What is the p-value for the test? p-value = (c) The MINITAB analysis uses the pooled estimate of o². Is the assumption of equal variances reasonable? Why or why not? (Round your answer to three decimal places.) The ratio of the larger of the two sample variances to the smaller is which is ---Select--than 3, so the assumption of equal variances ---Select--- reasonable.
Transcribed Image Text:(a) Do the data in the table present sufficient evidence to indicate a difference in the average prices of light tuna in water versus oil? Test using a = 0.05. State the null and alternative hypotheses. O Ho: (M₁M₂) = 0 versus H₂: (M₁ - H₂) <0 O Ho: (M₁M₂) < 0 versus H₂: (M₁-M₂) >0 O Ho: (M₁M₂) = 0 versus H₂: (μ₁ −μ₂) # 0 O Ho: (M₁M₂) 0 versus H₂: (μ₁ −μ₂) = 0 O Ho: (M₁M₂) = 0 versus H₂: (M₁M₂) >0 State the test statistic. t = State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three places.) t> State the conclusion. O Ho is rejected. There is insufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. O Ho is not rejected. There is sufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. O Ho is not rejected. There is insufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. O Ho is rejected. There is sufficient evidence to conclude that there is a difference in the average prices of light tuna in water versus oil. (b) What is the p-value for the test? p-value = (c) The MINITAB analysis uses the pooled estimate of o². Is the assumption of equal variances reasonable? Why or why not? (Round your answer to three decimal places.) The ratio of the larger of the two sample variances to the smaller is which is ---Select--than 3, so the assumption of equal variances ---Select--- reasonable.
Data on the estimated average price for a variety of different brands of tuna, based on prices paid nationally in supermarkets, are shown in the following table. Use the MINITAB printout to answer the questions in parts (a)-(c). (Use the exact values found in the MINITAB output.) Light Tuna in Water 0.97 0.51 1.94 1.39 1.94 0.68 1.21 1.14 1.32 0.60 0.83 0.61 1.77 0.63 0.67 0.62 0.67 0.69 1.21 0.62 0.58 0.68 Light Tuna in Oil 2.54 0.64 Sample Light Water Light Oil Two-Sample T-Test and CI: Light Water, Light Oil Descriptive Statistics N 14 Difference -0.256 Estimation for Difference T-Value -1.18 0.69 11 Test Null hypothesis Pooled StDev 0.536 Alternative hypothesis Mean 0.894 1.149 DF 23 StDev 0.402 0.672 H₂ M₁ H₂: M₂ 95% CI for difference (-0.703, 0.192) M₂ = 0 M₂ #0 SE Mean 0.11 0.20 P-Value 0.249
Transcribed Image Text:Data on the estimated average price for a variety of different brands of tuna, based on prices paid nationally in supermarkets, are shown in the following table. Use the MINITAB printout to answer the questions in parts (a)-(c). (Use the exact values found in the MINITAB output.) Light Tuna in Water 0.97 0.51 1.94 1.39 1.94 0.68 1.21 1.14 1.32 0.60 0.83 0.61 1.77 0.63 0.67 0.62 0.67 0.69 1.21 0.62 0.58 0.68 Light Tuna in Oil 2.54 0.64 Sample Light Water Light Oil Two-Sample T-Test and CI: Light Water, Light Oil Descriptive Statistics N 14 Difference -0.256 Estimation for Difference T-Value -1.18 0.69 11 Test Null hypothesis Pooled StDev 0.536 Alternative hypothesis Mean 0.894 1.149 DF 23 StDev 0.402 0.672 H₂ M₁ H₂: M₂ 95% CI for difference (-0.703, 0.192) M₂ = 0 M₂ #0 SE Mean 0.11 0.20 P-Value 0.249
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