1100.64 = 632.17a - 121.45b + TE 1431.09 = 121.45a +632.17b + TN 1678.39 = 355.20a + 642.07b + T 254.15=-642.07a +355.20b + TN (b) The simultaneous solution of the above four equations yields the following: a = 1.11964 b = 1.16285 T=534.07 TN = 559.99

1100.64 = 632.17a - 121.45b + TE 1431.09 = 121.45a +632.17b + TN 1678.39 = 355.20a + 642.07b + T 254.15=-642.07a +355.20b + TN (b) The simultaneous solution of the above four equations yields the following: a = 1.11964 b = 1.16285 T=534.07 TN = 559.99

Name: please explain, how do you get the results of a, b, TE, TN like that?
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Description: please explain, how do you get the results of a, b, TE, TN like that? 1100.64 = 632.17a – 121.45b +T.|1431.09 = 121.45a + 632.17b +T,%3DN1678.39 = 355.20a + 642.07b +T254.15 = -642.07a +355.20b + TN(b) The simultaneous solution of the above four equa

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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