Scores for a common standardized college aptitude test are normally distributed with a mean of 493 and a standard deviation of 104. Randomly selected men are given a Prepartion Course before taking this test. Assume, for sake of argument, that the Preparation Course has no effect on people's test scores. If 1 of the men is randomly selected, find the probability that his score is at least 548.6. P(X > 548.6) =  Enter your answer as a number accurate to 4 decimal places. If 14 of the men are randomly selected, find the probability that their mean score is at least 548.6. P(x-bar > 548.6) =

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Scores for a common standardized college aptitude test are normally distributed with a mean of 493 and a standard deviation of 104. Randomly selected men are given a Prepartion Course before taking this test. Assume, for sake of argument, that the Preparation Course has no effect on people's test scores.

If 1 of the men is randomly selected, find the probability that his score is at least 548.6.
P(X > 548.6) = 
Enter your answer as a number accurate to 4 decimal places.

If 14 of the men are randomly selected, find the probability that their mean score is at least 548.6.
P(x-bar > 548.6) =

Please explain how you get this on calc (ti) and how to use the Z table. Thank you. 

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