Scores for a common standardized college aptitude test are normally distributed with a mean of 480 and a standard deviation of 114. Randomly selected men are given a Test Preparation Course before taking this test. Assume, for sake of argument, that the preparation course has no effect.If 1 of the men is randomly selected, find the probability that his score is at least 521.2.P(X > 521.2) = Enter your answer as a number accurate to 4 decimal places.If 15 of the men are randomly selected, find the probability that their mean score is at least 521.2.P(M > 521.2) = Enter your answer as a number accurate to 4 decimal places.Assume that any probability less than 5% is sufficient evidence to conclude that the preparation course does help men do better. If the random sample of 15 men does result in a mean score of 521.2, is there strong evidence to support the claim that the course is actually effective?No. The probability indicates that it is too possible by chance alone to randomly select a group of students with a mean as high as 521.2.Yes. The probability indicates that it is (highly ?) unlikely that by chance, a randomly selected group of students would get a mean as high as 521.2. Scores for a common standardized college aptitude test arenormally distributed with a mean of 480 and a standarddeviation of 114. Randomly selected men are given a TestPreparation Course before taking this test. Assume, for sakeof argument, that the preparation course has no effect.If 1 of the men is randomly selected, find the probabilitythat his score is at least 521.2.P(X> 521.2) =Enter your answer as a number accurate to 4 decimalplaces.If 15 of the men are randomly selected, find the probabilitythat their mean score is at least 521.2.P(M> 521.2) =Enter your answer as a number accurate to 4 decimalplaces.Assume that any probability less than 5% is sufficientevidence to conclude that the preparation course does helpmen do better. If the random sample of 15 men does resultin a mean score of 521.2, is there strong evidence tosupport the claim that the course is actually effective?O No. The probability indicates that it is too possibleby chance alone to randomly select a group ofstudents with a mean as high as 521.2.O Yes. The probability indicates that it is (highly?)unlikely that by chance, a randomly selected group ofstudents would get a mean as high as 521.2.

Mean ()= 480standard deviation ()=114

Answered: Scores for a common standardized…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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Scores for a common standardized college aptitude test are normally distributed with a mean of 480 and a standard deviation of 114. Randomly selected men are given a Test Preparation Course before taking this test. Assume, for sake of argument, that the preparation course has no effect. If 1 of the men is randomly selected, find the probability that his score is at least 521.2. P(X > 521.2) = Enter your answer as a number accurate to 4 decimal places. If 15 of the men are randomly selected, find the probability that their mean score is at least 521.2. P(M > 521.2) = Enter your answer as a number accurate to 4 decimal places. Assume that any probability less than 5% is sufficient evidence to conclude that the preparation course does help men do better. If the random sample of 15 men does result in a mean score of 521.2, is there strong evidence to support the claim that the course is actually effective? No. The probability indicates that it is too possible by chance alone to randomly select a group of students with a mean as high as 521.2. Yes. The probability indicates that it is (highly ?) unlikely that by chance, a randomly selected group of students would get a mean as high as 521.2.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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