Shear Equation V(x) = F V(x) V(x) V(x) Shear Diagram -x=L -x=L -x=L Moment Equation M(x) = -F(L-x) M(x) Moment Diagram FL M(x) x=L -x=L if 0 ≤ x

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter8: Engineering Materials
Section: Chapter Questions
Problem 85CQ
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Fill in the remainder of the table. Report the sign of your answers relative to theconvention for internal shear force and bending moment analysis

Shear Equation
V(x) = F
V(x)
V(x)
V(x)
Shear Diagram
-x=L
-x=L
-x=L
Moment Equation
M(x) = -F(L-x)
M(x)
Moment Diagram
FL
M(x)
x=L
-x=L
if 0 ≤ x <L/2: M(x) =-
if L/2<xsL:M(x) =
M(x)
(M/L)x
M/2- (M/L)(x-L/2)
x=L
Transcribed Image Text:Shear Equation V(x) = F V(x) V(x) V(x) Shear Diagram -x=L -x=L -x=L Moment Equation M(x) = -F(L-x) M(x) Moment Diagram FL M(x) x=L -x=L if 0 ≤ x <L/2: M(x) =- if L/2<xsL:M(x) = M(x) (M/L)x M/2- (M/L)(x-L/2) x=L
Schematic
Diagram
NA
MA
Free Body Diagram
cut at supports
x=0
VA = F
NA = 0
LL
B
MA = FL
M(x)
NA
N(x)
ΜΑ
√(x)
Free Body Diagram
F
to expose internal forces
M(x)
V(x)
(either ok)
N(x)
A
x=0
L/2
FL
B
A
M
13
L/2
L
B
Transcribed Image Text:Schematic Diagram NA MA Free Body Diagram cut at supports x=0 VA = F NA = 0 LL B MA = FL M(x) NA N(x) ΜΑ √(x) Free Body Diagram F to expose internal forces M(x) V(x) (either ok) N(x) A x=0 L/2 FL B A M 13 L/2 L B
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