Say whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option): Domain: A = {1,2,3} Codomain: B = {w, x, y, z) f = {(3,w), (2,z), (1,z)} O Injective O Surjective None O Bijective
Say whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option): Domain: A = {1,2,3} Codomain: B = {w, x, y, z) f = {(3,w), (2,z), (1,z)} O Injective O Surjective None O Bijective
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Need help with this foundations of mathematics homework problem. I had two math tutors from bartleby answer this problem and one said the answer was none and the other said the answer was injective. I don't know which answers are correct.

Transcribed Image Text:**Question:**
Determine whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option):
- **Domain:** A = {1, 2, 3}
- **Codomain:** B = {w, x, y, z}
- **Function:** f = {(3, w), (2, z), (1, z)}
**Options:**
- ○ Injective
- ○ Surjective
- ○ None
- ○ Bijective
**Explanation:**
To analyze the function \( f \), note the mappings:
- 3 maps to w
- 2 maps to z
- 1 maps to z
**Injective (One-to-One):**
A function is injective if every element of the domain maps to a unique element in the codomain. In this case, since both 2 and 1 map to z, the function is not injective.
**Surjective (Onto):**
A function is surjective if every element of the codomain is mapped by some element of the domain. Here, x and y in the codomain are not mapped by any element from the domain, so the function is not surjective.
**Bijective (One-to-One and Onto):**
A function is bijective if it is both injective and surjective. Since this function is neither, it is not bijective.
**Conclusion:**
The appropriate selection is "None" because the function is neither injective, surjective, nor bijective.
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