Sand o' = 40° c' = 0 y = 16.5 kN/m3 1.5 m FIGURE 6.24 A continuous foundation with load eccentricity 2 m Eq. 6.67 9ule) = qu 1-
Sand o' = 40° c' = 0 y = 16.5 kN/m3 1.5 m FIGURE 6.24 A continuous foundation with load eccentricity 2 m Eq. 6.67 9ule) = qu 1-
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
A continuous foundation is shown in Figure 6.24. If the load eccentricity is 0.2 m, determine the ultimate load, Qu, per unit length of the foundation. Use Meyerhof’s effective area method.
Solve this using attached equation
![Sand
o' = 40°
c' = 0
y = 16.5 kN/m3
1.5 m
FIGURE 6.24 A continuous foundation with load
eccentricity
2 m
Eq. 6.67
9ule) = qu
1-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb87ef4c9-2379-4ac3-a41f-3a4c6bbb6b3a%2F120e40a8-9f33-4f17-a763-a7b0dcad863a%2Ftjdt67k_processed.png&w=3840&q=75)
Transcribed Image Text:Sand
o' = 40°
c' = 0
y = 16.5 kN/m3
1.5 m
FIGURE 6.24 A continuous foundation with load
eccentricity
2 m
Eq. 6.67
9ule) = qu
1-
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