A continuous foundation is shown. If the load eccentricity is 0.2m, determine the ultimate load, Qu, per unit length of foundation using Meyerhoff's Method. Sand 1.5 m $' = 40° c'=0 y = 16.5 kN/m³ 2m-

A continuous foundation is shown. If the load eccentricity is 0.2m, determine the ultimate load, Qu, per unit length of foundation using Meyerhoff's Method. Sand 1.5 m $' = 40° c'=0 y = 16.5 kN/m³ 2m-

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter9: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 9.15P

See similar textbooks

Related questions

Q: 3 Given: T- shape foundation as shown in figure is loaded with a uniform load of 120 kN/m².…

A: T shaped foundation loaded with uniform load q = 120 kPa

Q: For the rigid shallow foundation (2*4m) shown in Fig, calculate Immediate settlement the center of…

A: Given: net pressure, qo = 100 kPa Poisson ratio, μ=0.3 B = 2 m L = 4 m H = 3.5+0.5=4 m

Q: A flexible foundation measuring 1.5 m x 3 m is supported by a saturated clay. Given: Dr = 1.2 m, H =…

A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: A column foundation (Figure P4.5) is 3 m x 2 m in plan. Given: Df = 1.5 m, Φ' = 25°, c' = 70 kN/m2.…

A: It is the net soil pressure that can be safely applied to the soil considering only shear failure.…

Q: 2 ft 24 ft 24 ft 24 ft 2 ft Problem 4 B E F G 3 ft DL=190 kip DL-100 kip DL=180 kip LL = 60 kip LL=…

A: Given data: Size of the mat = 76 ft by 96 ft Column size = 24 in. by 24 in. qall(net)=1.5 kip/ft2…

Q: For a shallow foundation shown below: Estimate the moments about the x- and y-axis; assume that the…

Q: 9.3 Given: T-shape foundation as shown in figure is loaded with a uniform load of 120 kN/m².…

A: T shaped foundation loaded with uniform load q = 120 kPa

Q: A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC)…

A: Solution Given Data γ= 19.24 kN/m3Cc=0.25e0=0.8c'=25 kPaFOS= 4

Q: A long foundation 0.6 m wide carries a line load of 100 kN/m. Calculate the vertical stress, at a…

A: Given: The width of the foundation is 0.6 m. The line load is 100 kN/m. The coordinate x is 2.75 m.…

Q: Question 2) For a shallow foundation shown below: A. Estimate the ultimate bearing capacity when the…

Q: For a square foundation that is B × B in plan, D; = 2 m; vertical gross allowable load, Qall = 3330…

A: Question is based on foundation engineering. Dimension's of square foundation, unit weight of soil…

Q: A continuous foundation is shown in Figure is to be constructed on a sand deposit. If the load…

A: the load eccentricity e=0.2 mthe width of foundation B=2 m,the depth of the foundation Df =1.5 m

Q: • A 1.8 m x 2.5 m foundation is shown in Figure. If the load eccentricity eB 0.45 m and e₁ = 0.30…

Q: A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC)…

A: Given data load = 500 KN Foundation is square that means Same dimensions Depth of foundation= 2m…

Q: A flexible foundation measuring 1.5 m x 3 m is supported by a saturated clay. Given: Dr = 1.2 m, H 3…

A: The formula to calculate the average elastic settlement is given by, Se=A1A2q0BEs…

Q: Refer to Figure 5.2 and consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m,…

A: Solution Given Data B = 1.5 m, L = 2.5 m, Df = 1.2 m, H = 0.9 m, Φ' = 40º, c' = 0, and γ = 17 kN/m3.…

Q: continuous foundation, supported by sand,

Q: 10. A flexible foundation is subjected to a uniformly distributed load of q-500 kN/m². Table 3 could…

Q: H.Q 1 Consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m, H =0.9 m, o' =…

A: The given data is as follows: Rectangular foundation,B=1.5 mL=2.5 mDf=1.2 mH=0.9 mϕ'=40∘c'=0γ=17…

Q: An eccentrically loaded continuous foundation is shown in Figure P4.11. Determine the ultimate load…

A: Determining the centric ultimate bearing capacity with the help of relation qult…

Q: The shallow foundation shown below measures 2 m x 3 m and is subjected to a centric load and a…

A: Solution: Shallow foundation measure=2×3 meB=0.2 meL=0.3 mdepth of foundation=30°Factor of…

Q: A column foundation (Figure P3.5) is 3 m x 2 m in plan. Given: D; = 2 m, O' = 25°, c' = 50 kN/m?.…

Q: ELABORATE Try solving the following problem: Practice Problem: A rigid foundation is subjected to a…

A: P = 550KN L = 3m B = 2m Df= 1.5m H = 5m Es= 13500knN/m2 μs = 0.5 It has been asked in the question…

Q: 3. A square foundation is constructed in a soil deposit as shown in the figure below. Assume that…

A: Formula to calculate the ultimate bearing capacity of footing is given by qu = C'Nc Fcs Fcd Fci + q…

Q: A shallow foundation measuring 1.75 m x 1.75 m is to be constructed over a layer of sand to support…

A: B = 1.75m P = 400 kN Df = 1 m N60 = 12

Q: What will be the net allowable bearing capacity of a foundation planned to be 1.83 m 3 1.83 m? Let…

Q: Example 12.6 A square foundation is shown in Figure 12.9. Assume that the load eccentricity e 0.5…

Q: Question 1) For a shallow foundation measuring (1.7 m x 2.2 m) as shown below: , A. Estimate the…

A: Given, qnet = 1.2 MN/m2 B = 1.7 m

Q: A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, p' = 30°, c' = 80 kN/m². Using the…

Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

A continuous foundation is shown. If the load eccentricity is 0.2m, determine the ultimate load, Qu, per unit length of foundation using Meyerhoff's Method.
Sand
1.5 m
$' = 40°
c'=0
Y = 16.5 kN/m³
Select the correct response:
3584.32
4681.37
6813.52
5261.36
2 m

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Given Data

VIEW

Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 6.33). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination = 18. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (6.89)] b. for a reinforced type of loading [Eq. (6.90)]
o T ☺ ť (Q4): For the soil profile shown in figure (2) find the difference in stress in (kPa) at point located at a depth (10m) under the center of the circular foundation when using the below formulas and when using the approximation method 1 Ao, = q [(R/2)* + 1] Dia4m q0.21 N/mm N.G.S Sand e0.8 G.-2.6 3m W.L e0.7 G-2.7 5m Clayey - Sand e045 G.-2.68 مر ر ل لأعلى لاستعراض الفلاتر إضافة شرح. .. mum < II
The shallow foundation shown below measures 2 m x 3 m and is subjected to a centric load and a moment. If eg = 0.2 m, ez = 0.3 m, and the depth of foundation is 1 m, determine the allowable load the foundation can carry. Use a factor of safety of 3. For the soil, we are told that the unit weight, y = 17 kn/m³, friction angle o' = 30°, and the cohesion, c' = 0. Qult B× L Qult eL Qult Qaln My B
A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC) clay soil as shown in the below figure. The maximum acceptable settlement for the foundation is equal to 2.0 inches (5 cm), and the safety factor against bearing capacity is FS = 4. Determine the size of foundation. (Note: To simplify the calculations, ignore both the elastic settlement and secondary compression settlement. Also consider Ao'ave = 4o'm) Q = 500 kN Ysat = 19.24 kN/m³ eo = 0.8 C. = 0.25 p'= 0 c' = 25 kPa FS again Bearing Capacity = 4 Acceptable settlement = 2.0 inches 2 m В ХВ 10 m
subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING
Question 2) For a shallow foundation shown below: A. Estimate the ultimate bearing capacity when the water table located at a depth of 2 m below the ground surface. B. Estimate the moments about the x- and y-axis; assume that the foundation is subjected to a vertical load and a moment. If eg and eL is 0.33 m and 0.12 m, respectively. G.S Iz 2 m (2 m x 3 m) Silty clay Yo=17 kN/m³ , Ysat = 20 kN/m3 %3D 6 m c'=78 kN/m? 0'=35° Shear modulus=250 kN/m? CS Scanned with CamScanner
Example 12.6 A square foundation is shown in Figure 12.9. Assume that the load eccentricity e 0.5 ft. Determine the ultimate load, Qut Sand y = 115 lb/ft d' = 30° 5ft X5ft c' 0 Figure 12.9
3 Given: T- shape foundation as shown in figure is loaded with a uniform load of 120 kN/m². Required: the increment in vertical stress at point (P) at a depth of 5m. 0.6 0.6 0.6 0.6 3m m n I, 1.5 0.3 0.0629 1.2 0.1431 9m 3m 0.1069
i5:) For the continuous foundation show below, determine the amount of ultimate load for each meter length of the foundation. Consider the one-dimension eccentricity. : -) = 105 Ib/ft: Groundwater table 2 ft 4 ft Ysat = I18 lb/ft c' = 400 lb/ft? +2 ft - 25° 5 ft
help me
Please solve only part 5
A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC) clay soil as shown in the below figure. The maximum acceptable settlement for the foundation is equal to 2.0 inches (5 cm), and the safety factor against bearing capacity is FS = 4. Determine the size of foundation. (Note: To simplify the calculations, ignore both the elastic settlement and secondary compression settlement. Also consider 4o'ave = 40'm) Q = 500 kN Ysat = 19.24 kN/m³ en = 0.8 C. = 0.25 p'= 0 c'= 25 kPa 2 m B ×B FS again Bearing Capacity = 4 Acceptable settlement = 2.0 inches 10 m