Calculate the elastic settlement under the center of the flexible foundation shown in the figure below using Schmertmann's method. Assume t 1 year, ysoil 120 lb/ft and divide the soil into 1.5 ft intervals. Note that the equations of I, are given in the sketch below for your convenience. Assume the surcharge applied by the foundation is Ao=25,000 lb/ft2.
Calculate the elastic settlement under the center of the flexible foundation shown in the figure below using Schmertmann's method. Assume t 1 year, ysoil 120 lb/ft and divide the soil into 1.5 ft intervals. Note that the equations of I, are given in the sketch below for your convenience. Assume the surcharge applied by the foundation is Ao=25,000 lb/ft2.
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter17: Subsoil Exploration
Section: Chapter Questions
Problem 17.10P
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![8) Calculate the elastic settlement under the center of the flexible foundation shown in the
figure below using Schmertmann's method. Assume t = 1 year, ysoil=120 lb/ft and
divide the soil into 1.5 ft intervals. Note that the equations of I, are given in the sketch
below for your convenience. Assume the surcharge applied by the foundation is
Ao=25,000 lb/ft.
Soil
D=3'
Δσ
B = 6', L = 24'
E, (Ib/ft').
42) = 0.1 + 2*0.4/3
120,000
3'
3'
240,000
6'
142) = 0.5 - 0.5 (z-3)/9-
9"
9'
-360,000
12'
12'-
z(ft)
z(ft),](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2656d69b-329e-4eaa-b7b6-ba4776355dfa%2F452933b7-af47-44b2-a4cd-244de4eb4aab%2Fwvu69qe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8) Calculate the elastic settlement under the center of the flexible foundation shown in the
figure below using Schmertmann's method. Assume t = 1 year, ysoil=120 lb/ft and
divide the soil into 1.5 ft intervals. Note that the equations of I, are given in the sketch
below for your convenience. Assume the surcharge applied by the foundation is
Ao=25,000 lb/ft.
Soil
D=3'
Δσ
B = 6', L = 24'
E, (Ib/ft').
42) = 0.1 + 2*0.4/3
120,000
3'
3'
240,000
6'
142) = 0.5 - 0.5 (z-3)/9-
9"
9'
-360,000
12'
12'-
z(ft)
z(ft),
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