Sampling Distributions This exercise is to be completed in a group. For the population:     1          3          5          7          9 Find the mean and standard deviation.   U = 1+3+5+7+9 / 5   = 25/5 The Mean is  = 5 n= 5 The Median is = 5 Then standard deviation is = 2.828 Round to =2.83 Now determine how many samples of size 2 can be formed from this population of size 5, disregarding order. Use the appropriate formula. n=5    x=2     = n! / x! (n-x)!     = 5! / 2! (5-2)!     = 10  List all the samples of size 2 that can be formed from this population. Be sure the list is consistent with the answer obtained from the formula. Otherwise, check your work.  (1,3), (1,5), (1,7), (1,9), (3,5), (3,7), (3,9), (5,7), (5,9) (7,9)   Calculate the mean of each of the samples of size 2. 1,3 = (1+3)/2 = 2 1,5 = (1+5)/2 = 3 1,7 = (1+7)/2 = 4 1,9 = (1+9)/2 =5 3,5 =(3+5)/2 = 4 3,7 = (3+7)/2 =5 3,9 =(3+9)/2 = 6 5,7 = (5+7)/2= 6 5,9 =(5+9)/2 = 7 7,9 = (7+9)/2 = 8   Create a probability distribution of all the sample means from the sample of size 2. (HINT: If you have a mean of 7 in the list of sample means and it occurs 3 times out of 10, then the probability is 0.3 for that mean value.)   Calculate the mean and standard deviation of that probability distribution using the appropriate formulas.   How do the measures of the probability distribution compare to the measures from the original population?  What type of probability distribution appears to be formed?  Summarize any conclusions that would be fair to draw from these results.

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Sampling Distributions

This exercise is to be completed in a group.

For the population:     1          3          5          7          9

Find the mean and standard deviation.

  U = 1+3+5+7+9 / 5

  = 25/5

The Mean is  = 5

n= 5

The Median is = 5

Then standard deviation is = 2.828 Round to =2.83

Now determine how many samples of size 2 can be formed from this population of size 5, disregarding order. Use the appropriate formula.

n=5    x=2

    = n! / x! (n-x)!

    = 5! / 2! (5-2)!

    = 10

 List all the samples of size 2 that can be formed from this population. Be sure the list is consistent with the answer obtained from the formula. Otherwise, check your work.

 (1,3), (1,5), (1,7), (1,9), (3,5), (3,7), (3,9), (5,7), (5,9) (7,9)

  Calculate the mean of each of the samples of size 2.

1,3 = (1+3)/2 = 2

1,5 = (1+5)/2 = 3

1,7 = (1+7)/2 = 4

1,9 = (1+9)/2 =5

3,5 =(3+5)/2 = 4

3,7 = (3+7)/2 =5

3,9 =(3+9)/2 = 6

5,7 = (5+7)/2= 6

5,9 =(5+9)/2 = 7

7,9 = (7+9)/2 = 8

 

Create a probability distribution of all the sample means from the sample of size 2. (HINT: If you have a mean of 7 in the list of sample means and it occurs 3 times out of 10, then the probability is 0.3 for that mean value.)

 

Calculate the mean and standard deviation of that probability distribution using the appropriate formulas.

 

How do the measures of the probability distribution compare to the measures from the original population?  What type of probability distribution appears to be formed?  Summarize any conclusions that would be fair to draw from these results.



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