sample stalact (a type rock Tormation) a glow produced the following lengths in cm: e.6 16.9 15.1 14.3 15.9 17.2 13.0 17.1 15.4 16.2 4.5 20.3 21.2 15.7 Assuming that this sample came from a normal population, calculate a 95% confidence interval for the mean length of stalactites in the cave.
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- The health of the bear population in Yellowstone National park is monitored by periodic measurements taken from anesthetized bears. A sample 54 bears has a mean weight of 182.9 lb. And mean is known as 121.8 lb. find a 99% confidence estimate of the population of all bear weightsThe health of the bear population in Yellowstone National Part is monitored by periodic measurements taken from anesthetized bears. A sample 54 bears has a mean weight of 182.9 lb. and o is know as 121.8 lb., find a 99% confidence estimate of the population of all bear weights.A forester with the National Park Service was tasked with estimating the average age of the bald cypress trees (Taxodium distichum) in Big Cypress Swamp - a region in Everglades National Park. The forester extracted core samples from 37 randomly selected bald cypress trees in Big Cypress Swamp. The mean age of the sample was 254.2 years with a standard deviation of 22 years. Using a 95% confidence level, determine the margin of error, E, and a confidence interval for the average age of all bald cypress trees in Big Cypress Swamp. Report the confidence interval using interval notation. Round solutions to two decimal places, if necessary. The margin of error is given by E= A 95% confidence interval is given by=
- In a random sample of twelvetwelve people, the mean driving distance to work was 24.624.6 miles and the standard deviation was 4.54.5 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 9999% confidence interval for the population mean muμ. Interpret the results.How heavy a load, in pounds, is needed to pull apart pieces of Douglas fir 4 in. Iong and 1.5 in. wide with a standard deviation o of 3000 lbs? Estimate the mean load u needed to pull apart the pieces of wood to within plus or minus 600 lbs with 95% confidence. Determine how large of a sample size n is needed.Professor Oak ran a recent study and found that the mushroom stalk height for paras Pokémon are normally distributed with a mean of 18.05 mm and a standard deviation of1.93mm. A.) Find percentage of paras that have a mushroom stalk between 16mm and 17mm B.) Find the recent age of Paras that have a mushroom stalk height exceeding 19mm C.) Determine the quartile for the mushroom stalk height for paras D.)Obtian the95th percentile for Paras mushroom stalk height
- A manufacturer of college textbooks is interested in the strength of the bindings produced by a particular binding machine. Strength can be measured by recording the force required to pull the pages from the binding. If this force is measured in pounds, how many books should be tested to estimate the average force required to break the binding within .5 pounds with 90% confidence. Assume the population standard deviation is 0.4 pounds. 2.A forester with the National Park Service was tasked with estimating the average age of the bald cypress trees (Taxodium distichum) in Big Cypress Swamp - a region in Everglades National Park. The forester extracted core samples from 35 randomly selected bald cypress trees in Big Cypress Swamp. The mean age of the sample was 331.8 years with a standard deviation of 24.5 years. Using a 90% confidence level, determine the margin of error, E, and a confidence interval for the average age of all bald cypress trees in Big Cypress Swamp. Report the confidence interval using interval notation. Round solutions to two decimal places, if necessary. The margin of error is given by Incorrect. 6.79A 90% confidence interval is given by $324.80,338.80$Incorrect invalid interval notation. .An auditor for a large oil corporation has taken a random sample of monthly credit card charges for 32 individual (noncorporate) accounts. She found a mean of $81.76. Assume that the population standard deviation is 48.2. A 98% confidence interval estimate for the population mean of individual credit card charges would be Select one: a. 81.76 ± 112.94 b. 81.76 ± 22.0 c. 81.76 ± 19.89 d. 81.76 ± 16.72 e. 81.76 ± 2.33
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