sample stalact (a type rock Tormation) a glow produced the following lengths in cm: e.6 16.9 15.1 14.3 15.9 17.2 13.0 17.1 15.4 16.2 4.5 20.3 21.2 15.7 Assuming that this sample came from a normal population, calculate a 95% confidence interval for the mean length of stalactites in the cave.
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- The health of the bear population in Yellowstone National park is monitored by periodic measurements taken from anesthetized bears. A sample 54 bears has a mean weight of 182.9 lb. And mean is known as 121.8 lb. find a 99% confidence estimate of the population of all bear weightsThe health of the bear population in Yellowstone National Part is monitored by periodic measurements taken from anesthetized bears. A sample 54 bears has a mean weight of 182.9 lb. and o is know as 121.8 lb., find a 99% confidence estimate of the population of all bear weights.A forester with the National Park Service was tasked with estimating the average age of the bald cypress trees (Taxodium distichum) in Big Cypress Swamp - a region in Everglades National Park. The forester extracted core samples from 37 randomly selected bald cypress trees in Big Cypress Swamp. The mean age of the sample was 254.2 years with a standard deviation of 22 years. Using a 95% confidence level, determine the margin of error, E, and a confidence interval for the average age of all bald cypress trees in Big Cypress Swamp. Report the confidence interval using interval notation. Round solutions to two decimal places, if necessary. The margin of error is given by E= A 95% confidence interval is given by=
- The average height of students at a random place from an SRS of 12 students gave a standard deviation of 2.5 feet. Construct a 95% confidence interval for the standard deviation of the height of students at the place. Assume normality for the data. a) (1.271, 6.245) b) (0.771, 10.245) c) (1.771, 4.245) d) (7.771, 9.245) e) (4.771, 10.245) f) None of the aboveIn a random sample of twelvetwelve people, the mean driving distance to work was 24.624.6 miles and the standard deviation was 4.54.5 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 9999% confidence interval for the population mean muμ. Interpret the results.The average height of students in a state from an SRS of 17 students gave a standard deviation of 2.9 feet. Construct a 95% confidence interval for the standard deviation of the height of students in a state. Assume normality for the data. a) (1.160, 9.413) b) (6.160, 11.413) c) (2.160, 4.413) d) (4.160, 9.413) e) (1.660, 8.413) f) None of the above
- A forester with the National Park Service was tasked with estimating the average age of the bald cypress trees (Taxodium distichum) in Big Cypress Swamp - a region in Everglades National Park. The forester extracted core samples from 35 randomly selected bald cypress trees in Big Cypress Swamp. The mean age of the sample was 331.8 years with a standard deviation of 24.5 years. Using a 90% confidence level, determine the margin of error, E, and a confidence interval for the average age of all bald cypress trees in Big Cypress Swamp. Report the confidence interval using interval notation. Round solutions to two decimal places, if necessary. The margin of error is given by Incorrect. 6.79A 90% confidence interval is given by $324.80,338.80$Incorrect invalid interval notation. .An auditor for a large oil corporation has taken a random sample of monthly credit card charges for 32 individual (noncorporate) accounts. She found a mean of $81.76. Assume that the population standard deviation is 48.2. A 98% confidence interval estimate for the population mean of individual credit card charges would be Select one: a. 81.76 ± 112.94 b. 81.76 ± 22.0 c. 81.76 ± 19.89 d. 81.76 ± 16.72 e. 81.76 ± 2.33A recent study investigated tractor skidding distances along a road in a forest. The skidding distances (in meters) were measured at 20 randomly selected road sites. The data are given in the accompanying table. A logger working on the road claims that the mean skidding distance is at least 425 meters. Is there sufficient evidence to refute this claim? Use a = 0.05. Click the icon to view the table. State the hypotheses to test if there is sufficient evidence to refute the claim that the mean skidding distance is at least 425 meters. Choose the correct answer below. А. Но: и 3D425 Ha: H#425 В. Но: и3 425 Hgi H 425 D. H : μέ 425 Hai H = 425 Calculate the value of the test statistic. 484 349 451 197 287 414 443 583 436 562 376 290 178 269 281 392 316 311 138 437 t = (Round to two decimal places as needed.) Calculate the p-value. Print Done p-value = (Round to four decimal places as needed.) Make the appropriate conclusion. Choose the correct answer below. O A. Do not reject Ho. There is…
- Find the 95% confidence interval (CI) and margin of error (ME) of the true mean weights of male college students given: n=14, ¯x=194.2 lb., s=12.8 lb. Interpret the results.The brightness of a television picture tube can be evaluated by measuring the amount of current required to achieve a particular brightness level. A sample of 10 tubes results in x = 317.2 and s = 15.7. Find (in microamps) a 99% confidence interval on mean current required. State any necessary assumptions about the underlying distribution of the data.A random sample of fifty-six 200-meter swims has a mean time of 3,86 minutes and the population standard deviation is 0.06 minutes. Construct a 90% confidence interval for the population mean time. Interpret the result The 90% confidence interval is (1 D. (Round to two decimal places as needed.)