A sample of 20 observations shows a sample mean of 290 and a sample standard deviation of 30. Provide a 90 per cent confidence interval estimate of the population variance. Select one: O a. 567 sa's 1690 O b. 567 so's l1790 O c. 657 sos1890 O d. 657 sa's1790 ge Next page
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- Identify the range, variance and standard deviation. show complete solutionsbelow are the numbers of years that archbishops and monarchs in a certain country lived after their election o ation. Assume that the two samples are independent simple random samples selected from normally distribute ations. Do not assume that the population standard deviations are equal. Use a 0.05 significance level to test th e mean longevity for archbishops is less than the mean for monarchs after coronation. All measurements are lick the icon to view the table of longevities of archbishops and monarchs. Longevities of archbishops and monarchs 17 Archbishops 17 14 16 3. 16 18 12 13 9. 16 11 11 15 17 7 18 10 20 16 Monarchs 11 19 14 14 17 15 16 14 12 15 16 Print Done 454 65 115The 0 in the numerator for the formula for the paired samples + test statistic represents the _____ hypothesis. a. mean difference score according to the alternative b. population standard deviation accordiing to the alternative c. population standard deviation according to the null d. mean difference score according to the null
- The Gidget Company makes widgets. If the production process is working properly, it turns out that the widgets are normally distributed with a hean length of at least 2.6 feet. Larger widgets can be used or altered but shorter widgets must be scrapped. You select a sample of 25 widgets, and the mean length is 2.46 feet and the sample standard deviation is 0.16 foot. Do you need to adjust the production equipment? Complete parts (a) through (d). Click here to view page 1 of the critical values for the t Distribution. Click here to view page 2 of the critical values for the t Distribution. a. If you test the null hypothesis at the 0.05 level of significance, what decision do you make using the critical value approach to hypothesis testing? What are the null and alternative hypotheses for this test? 'Α. H μ22.6 H4: µ 2.6 O C. Ho:H22.46 H,:H2.6 H,: µs2.6 O E. Ho: us2.46 H,:µ>2.46 OF. Ho:H<2.6 H1:µ22.6 What is the test statistic for this test? - 4.3750 (Round to four decimal places as…Listed below are the numbers of years that archbishops and monarchs in a certain country lived after their election or coronation. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean longevity for archbishops is less than the mean for monarchs after coronation. All measurements are in years. E Click the icon to view the table of longevities of archbishops and monarchs. ur ne What are the null and alternative hypotheses? Assume that population 1 consists of the longevity of archbishops and population 2 consists of the longevity of monarchs. OA Ho H SH2 B. Ho: H"P2 H >2 OD. Ho P=P2 H: 2 ru oC Ho H 2 The test statistic is. (Round to two decimal places as needed.) ite fo - X Longevities of Archbishops and Monarchs im 17 18 Archbishops 13 12 18 3 18 18 18 10 13 13 18 17 hat 13 O 12 14 15 13 17 10 13 19 14…A random sample of 82 women showed that the mean number of children reported was 1.87 with a standard deviation of 1.7 . (Interestingly, a sample of 82 men showed a mean of 1.3 children.) Complete parts (a) through (c) below. LOADING... Click the icon to view the t-table. Question content area bottom Part 1 a. Find a 95% confidence interval for the population mean number of children for women. Because the sample size is so large, you can use 1.96 for the critical value of t (which is the same as the critical value of z) if you do the calculations manually. Choose the correct answer below and, if necessary, fill in the answer boxes to complete your choice. (Type integers or decimals rounded to the nearest hundredth as needed. Use ascending order.)
- 3. Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11,12, 15. There are 10,000 total students. Average GPA: Unknown, StandardDeviation of GPA: 0.02 and it’s Normal.a. Find the mean and standard deviation for GPA.b. Calculate a 95% confidence interval for the populations mean GPA.c. Use Correlation formula to find r between GPA and Age.d. Find Regression Line Equation.e. If a student’s age is 13, what is the corresponding GPA?Use Chebyshevs rule and the empirical rule to describe the distribution of this data set. Count the actual number of observations that fall within one, two, and three standard deviations of the mean if the data set and compare these counts with the description of the the data set I developed.The average salary of 64 employee was 5400. Using historical data, we will assume that the population standard deviation is 260. Find the 90% confidence interval for the population mean salary. Select one: O a. 5400 + 53.46 O b. 5400 + 57.58 O c. 5400 + 55.52 O d. 5400 + 51.41
- In a sample of 7 observations, the values are 17, 11, 12, 13, 14, 15. 16. Find the 95% confidence interval for the population mean. O A. (5.00, 9.00) O B. (4.00, 8.00) OC (12.00, 16.00) OD.(11.00, 15.00)Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.select which of the three is correct