Sample Activity 1 What is the voltage across each capacitor? (Q = 36.76 μC) 25 V +9 3 μF C₁ 5 μF -q+q +q I C₂ -q+q 7 μF C₂ -q
Sample Activity 1 What is the voltage across each capacitor? (Q = 36.76 μC) 25 V +9 3 μF C₁ 5 μF -q+q +q I C₂ -q+q 7 μF C₂ -q
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NOTE: PLEASE USE THE FORMULA IN THE SAMPLE ACTIVITY.
![Sample Problem 1
What is the total charge (Qotal) and the charge on each capacitor of the given
diagram?
5 μF 7 μF
4HHH
C₂
+q
3 μF
C₁
25 V
Given:
V=25 V
C₁=3μF, C₂5μF, C₁=7μF
Required:
Qotal Q₂, Q₂, Q₁ =?
Formula:
c = or Q=CV and=++)
+q₁
C3
-9₁
I
C₂
Sample Activity 1
What is the voltage across each capacitor? (Q = 36.76 μC)
25 V
C₂
+q
-9₂
3 μF
C₁
-q+q
Solution:
1
+q₁
C₁
1
1
C-=(3μF + SUF+7AF)
Ceq
7μF
Quotal = CeqV
Quotal (3HF + SUF+7F)(25V)
Quotal (HF) (25V)
=
Quotal = (0.68 H) (25V)
Quotal = 36.76μC
5 μF
Capacitance in Parallel Connection
• When the capacitors are connected in parallel, each of the capacitors in the
circuit has direct interaction with the conductor. This results in the potential of
the capacitor to remain the same for the whole circuit
•The total charge is the sum of the individual charges.
C₂
-q+q
7 μF
C3
-q
Capacitors are connected
together in parallel when both of its
terminals are connected to each
V terminal of another capacitor.
◆B
Capacitance in Parallel Connection
Since The total charge is equal to the sum of the charges on the capacitors, the formula for
Charge Qal will be:
Qotal Q₁+Q₂+Q₂ (9)
Getting the equation for Charge from eq. 1 and writing with 2 capacitors will
give:
Q₁ = C₁V Q₂ = C₂V
The total charge of the combination, and thus the total charge on the equivalent capacitor is:
Q = Q₁ + Q₂ = V(C₁ + C₂) (10)
Dividing both sides of the equation by V to Derive C (equivalent capacitance) will give:
Q
Ceq = C₁ + C₁₂ (11)
The equivalent capacitance of a parallel combination equals the sum of the individual capacitances:
Ceq = C₁ + C₂ + C3 + + C₂ (12)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f9ca16d-6376-477b-9ec5-b2e0296e60a9%2F38a4b8af-153f-465d-93fd-b19f11d5545b%2Fz3kq6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sample Problem 1
What is the total charge (Qotal) and the charge on each capacitor of the given
diagram?
5 μF 7 μF
4HHH
C₂
+q
3 μF
C₁
25 V
Given:
V=25 V
C₁=3μF, C₂5μF, C₁=7μF
Required:
Qotal Q₂, Q₂, Q₁ =?
Formula:
c = or Q=CV and=++)
+q₁
C3
-9₁
I
C₂
Sample Activity 1
What is the voltage across each capacitor? (Q = 36.76 μC)
25 V
C₂
+q
-9₂
3 μF
C₁
-q+q
Solution:
1
+q₁
C₁
1
1
C-=(3μF + SUF+7AF)
Ceq
7μF
Quotal = CeqV
Quotal (3HF + SUF+7F)(25V)
Quotal (HF) (25V)
=
Quotal = (0.68 H) (25V)
Quotal = 36.76μC
5 μF
Capacitance in Parallel Connection
• When the capacitors are connected in parallel, each of the capacitors in the
circuit has direct interaction with the conductor. This results in the potential of
the capacitor to remain the same for the whole circuit
•The total charge is the sum of the individual charges.
C₂
-q+q
7 μF
C3
-q
Capacitors are connected
together in parallel when both of its
terminals are connected to each
V terminal of another capacitor.
◆B
Capacitance in Parallel Connection
Since The total charge is equal to the sum of the charges on the capacitors, the formula for
Charge Qal will be:
Qotal Q₁+Q₂+Q₂ (9)
Getting the equation for Charge from eq. 1 and writing with 2 capacitors will
give:
Q₁ = C₁V Q₂ = C₂V
The total charge of the combination, and thus the total charge on the equivalent capacitor is:
Q = Q₁ + Q₂ = V(C₁ + C₂) (10)
Dividing both sides of the equation by V to Derive C (equivalent capacitance) will give:
Q
Ceq = C₁ + C₁₂ (11)
The equivalent capacitance of a parallel combination equals the sum of the individual capacitances:
Ceq = C₁ + C₂ + C3 + + C₂ (12)
![15-18.5
15.-18.5 What is the (A) total charge (Qtotal) and the charge on each capacitor of
the given series diagram? What is the (B) voltage across each capacitor?
18.5-20 What is the (A) total charge (Qtotal) and the charge on across each parallel
capacitor? (B)Prove the total Voltage of 300V using the formula of Capacitance
125 μV
COK
10 μF
20 μF
|-:0 42/
q+q
C₁
C₂
1
30 μF
-q
18.5-20
40 μF
TC₁
50 μF
F
C₂
60 μF
C₁
300 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f9ca16d-6376-477b-9ec5-b2e0296e60a9%2F38a4b8af-153f-465d-93fd-b19f11d5545b%2Fp2sjsxb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:15-18.5
15.-18.5 What is the (A) total charge (Qtotal) and the charge on each capacitor of
the given series diagram? What is the (B) voltage across each capacitor?
18.5-20 What is the (A) total charge (Qtotal) and the charge on across each parallel
capacitor? (B)Prove the total Voltage of 300V using the formula of Capacitance
125 μV
COK
10 μF
20 μF
|-:0 42/
q+q
C₁
C₂
1
30 μF
-q
18.5-20
40 μF
TC₁
50 μF
F
C₂
60 μF
C₁
300 V
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