8.0 s, then comes to rest again. The velocity-versus-time plot for this car is given in FIGURE 2-37. What distance does the car cover in (a) the first 4.0 seconds of its motion and (b) the last 2.0 seconds of its motion? (c) What is the constant speed V that characterizes the middle portion of its motion? Velocity (m/s) O 2 4 Time (s) 6 8
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
I need help confirming solutions for sample problems. Image included, thanks!

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In part (a) of the solution you have:
22 = (.5)V (8 + 2)
I understand that 22 is total displacement, and 8 is the total seconds but where did you get the 2 from in (8 + 2)?
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