Sample 2 Assume that both populations are normally distributed. a) Test whether u, +µ2 at the a = 0.05 level of significance for the given sample data. b) Construct a 95% confidence interval about µ1 - 42- Sample 1 10 10.9 10 8.9 3.1 2.2 Click the icon to view the Student t-distribution table. A. Ho: H1 =H2, Hq: Hy> H2 B. Ho: H1 = H2, H1:H1 #H2 C. Ho: H1 = 42, H,:H1
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- Sample 2 Assume that both populations are normally distributed. a) Test whether µ, # µ, at the a = 0.05 level of significance for the given sample data. b) Construct a 95% confidence interval about u, - H2. Sample 1 17 13 17 14.3 3.5 3.1 E Click the icon to view the Student t-distribution table. A. Ho: H1 = H2, Hq: Hq # Hz O B. Ho: H1 = H2, H,: Hy H2 Determine the test statistic. t= - 1.15 (Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box(es) within your choice. (Round to three decimal places as needed.) O A. The critical value is O B. The lower critical value is -2.040. The upper critical value is 2.040. Should the hypothesis be rejected? Do not reject the null hypothesis because the test statistic is not in the critical region. b) Construct a 95% confidence interval about u, - H2. The confidence interval is the range from to| (Round to two decimal places as needed. Use ascending order.)To monitor complex chemical processes, chemical engineers will consider key process indicators, which may be just yield but most often depend on several quantities. Before trying to improve a process, 9 measurements were made on a key performance indicator. 123, 106, 114, 128, 113, 109, 120, 102, 111. Assume that the key performance indicator has a normal distribution. (a) Find the sample variance s? of the sample. (b) Find a 95% confidence interval for o?. (c) Find a 98% confidence interval for o.I need a hypothesis, description and interpretation, please! Thank you!!
- 10 K In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.6 and a standard deviation of 16.6. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <μDr. V. noticed that the more frequently a student is late or absent from class the worse he or she performs on the final exam. He decided to investigate. Dr. V. collected a random sample of 22 students. This sample includes the number of times a student is absent and their grades on the final exam. Discuss the implications of the calculated Statistical Power and the probability of a Type II Error. Significance Level: Use a 5% significance level. What is/are the Critical Value(s)? Calculate the coefficient of determination, r2, using Excel’s RSQ function. Explain what it means.un a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 2.8 and a standard deviation of 19.5. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. .... What is the confidence interval estimate of the population mean µ? mg/dL < µSamples of 100 8-hour shifts were randomly selected from the police records for each of two districts in a large city. The number of police emergency calls was recorded for each shift. The sample statistics are listed below. Region 1 2 Sample Size 100 100 Sample Mean 2.6 3.4 Sample Variance 1.24 2.54 Find a 90% confidence interval for the difference in the mean numbers of police emergency calls per shift between the two districts of the city. (Use μ₁ − μ₂. Round your answers to two decimal places.) calls per shift to calls per shiftFind the 90% confidence interval for the difference in the means.I need help with this question1) Treatment group Placebo group n₁ = 50 n2=100 x1 = 7.00 $1 = 1.00 x2 = 6.00 $2 = 2.00 Test the claim that the two samples come from populations with the same mean. Use a = .05. Draw it: Conclusion (full sentence): Ho= HA= Calculated value p-value Decision Find the 95% confidence interval for the difference between the two population means to the nearest hundredth.Can someone please help? Thank you.Your company sources motors from two suppliers: supplier A and supplier B. Your application requiresvery high maximum torque. You wish to know if there is a significant difference in maximum torque forthe motors from supplier A vs. supplier B. You sample 10 motors from each supplier and measure themaximum torque. The sample means and sample standard deviations are shown the following table. Is there evidence to conclude that one supplier is better than the other at a 95% confidence level?SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. 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