Sample 1Sample 2Independent random samples from normal populations produced the results shown in the table to the right. Complete parts a and b below.2.93.92.53.83.23.22.13.11.5...a. Calculate the pooled estimate of o.s = (Round to four decimal places as needed.)b. Find a 90% confidence interval for (H1-H2).The confidence interval is ( ).(Round to two decimal places as needed.)

For the given data Find Confidence interval

Answered: Sample 1 Sample 2 Independent random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Independent random samples were selected from two quantitative populations, with sample sizes, means, and variances given below. Population Sample Size Sample Mean Sample Variance 1 49 10.3 9.64 2 58 8.5 15.42 A 90% confidence interval for ₁-₂ is 0.68 to 2.92 and a 99% confidence interval for ₁-₂ is 0.05 to 3.55. Use these confidence intervals to answer the questions. Can you conclude with 99% confidence that there is a difference in the means for the two populations? Ⓒ Yes. The value #₁ - ₂2=0 is not in the interval which suggests that there is likely a difference between ₁ and 1₂. ₂ = 0 is not in the interval which does not suggest that there is a difference between and H1 #₂. O No. The value μ₁ - O No. The value μ₁ - ₂ = 0 is in the interval which does not suggest that there is a difference between and M₂ 1₂" and H₂ H₂² Yes. The value and H₂ H₂" = 0 is in the interval which suggests that there is likely a difference between M₁ - H₂ Can you conclude with 99% confidence that there is…
5.1 & 6.2 Question 13, 6.1.34 Part 1 of 2 Use the confidence interval to find the estimated margin of error. Then find the sample mean. HW Score: 44.29%, 15.5 of 35 O Points: 0 of 1 A store manager reports a confidence interval of (44.8,83.8) when estimating the mean price (in dollars) for the population of textbooks. The estimated margin of error is (Type an integer or a decimal.) Clear all his View an example Get more help - Q Search
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Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
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You are interested in finding a 90% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 14 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 5 8 11 10 12 19 24 6 26 10 26 10 26 15 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean commute for non-residential college students is between and miles. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of commute miles.
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Use the data to calculate the sample variance, s. (Round your answer to five decimal places.) n = 7: 1.6, 3.5, 1.6, 2.1, 3.1, 2.9, 3.0 %3D Construct a 95% confidence interval for the population variance, of. (Round your answers to two decimal places.) to Test Ho: = 0.8 versus H: of + 0.8 using a = 0.05. State the test statistic. (Round your answer to two decimal places.) x2 State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to two decimal places.) x2 > x² State the conclusion. H, is rejected. There is sufficient evidence to indicate that the population variance is different from 0.8. H, is rejected. There is insufficient evidence to indicate that the population variance is different from 0.8. H, is not rejected. There is sufficient evidence to indicate that the population variance is different from 0.8. O Ho is not rejected. There is insufficient evidence to indicate that the population variance is different from 0.8.
onsider the following results for two independent random samples taken from two populations. Sample 1 Sample 2 n 1 = 50 n 2 = 30 x 1 = 13.1 x 2 = 11.2 σ 1 = 2.3 σ 2 = 3 What is the point estimate of the difference between the two population means? (to 1 decimal) Provide a 90% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.( , ) Provide a 95% confidence interval for the difference between the two population means (to 2 decimals). Use z-table. If your answer is negative, enter minus (-) sign.( , )
Summary statistics for Chol: (a) Calculate a 95% confidence interval (Chapter 17) for the mean Cholesterol of heart disease patients. Use the t-distribution table and the Cholesterol summary statistics.Group by: HD HD n Mean Variance Std. dev. Std. err. Median Range Min Max Q1 Q3 No 164 242.64024 2857.606 53.45658 4.1742576 234.5 438 126 564 208.5 267.5 Yes 139 251.47482 2448.9468 49.486835 4.1974185 249 278 131 409 217 284
The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. Construct a 90% confidence interval for the population mean μ. 2.53.22.51.90.74.02.11.13.70.42.53.3

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