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SA skydiver is subject to two forces: gravity and air resistance. Falling vertically, she reaches terminal speed at some time after jumping from a plane. Since she is moving at a consta that time until her chute opens, we conclude from the work-kinetic energy theorem tha interval

SA skydiver is subject to two forces: gravity and air resistance. Falling vertically, she reaches terminal speed at some time after jumping from a plane. Since she is moving at a consta that time until her chute opens, we conclude from the work-kinetic energy theorem tha interval

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Score 5 A skydiver is subject to two forces: gravity and air resistance. Falling vertically, she reaches a constant terminal speed at some time after jumping from a plane. Since she is moving at a constant velocity from that time until her chute opens, we conclude from the work-kinetic energy theorem that, over that time interval the work done by gravity equals the negative of the work done by air resistance the work done by gravity is zero the work done by air resistance is zero er kinetic energy increases
Transcribed Image Text:Score 5 A skydiver is subject to two forces: gravity and air resistance. Falling vertically, she reaches a constant terminal speed at some time after jumping from a plane. Since she is moving at a constant velocity from that time until her chute opens, we conclude from the work-kinetic energy theorem that, over that time interval the work done by gravity equals the negative of the work done by air resistance the work done by gravity is zero the work done by air resistance is zero er kinetic energy increases
7A particle moves parallel to the x-axis. The net force on the particle increases with x according to the formula Fx = (120 N/m)x, where the force is in newtons when x is in meters. How much workidoes this force do on the particle as it moves from x = 0 to x = 0.50 m? 7.53 60J 30J 153
Transcribed Image Text:7A particle moves parallel to the x-axis. The net force on the particle increases with x according to the formula Fx = (120 N/m)x, where the force is in newtons when x is in meters. How much workidoes this force do on the particle as it moves from x = 0 to x = 0.50 m? 7.53 60J 30J 153
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