In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6968 subjects randomly selected from an online group involved with ears. There were 1288= surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomialdistribution.@2WView an example Get more help.SIdentify the null hypothesis and alternative hypothesis.XA. Ho: p<0.2H₁: p=0.2OC. Ho: p*0.2H₁: p=0.2andOE. Ho: p=0.2H₁: p=0.2двThe test statistic is z=₁(Round to two decimal places as needed.)X380F3EDC$48RF%5V&TG1 N6BMacBook AirF6YI'H&7N44F7U√iOB. Ho: p=0.2H₁: p>0.2JOD. Ho:p>0.2H₁: p=0.2*8F. H₂:p=0.2H₁: p<0.2DIIIM1₂(9K(1,0)DOMoreFOO<I)OLF10PClear all.:;I{+[command option=Check answer11?1I4mF121xdelete

Given that Sample size n=6970 Favorable cases x =1285 Sample proportion p^=x/n =1288/6968 =0.1848

Answered: s returned. Use a 0.01 significance…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of people who own cats is smaller than 10% at the 0.025 significance level. The null and alternative hypothesis would be: Ho p ≤ 0.1 Ho:μ = 0.1 Ho:p 0.1 H₁:p> 0.1 H₁:μ 0.1 H₁:p ‡ 0.1 O The test is: = left-tailed two-tailed right-tailed Based on this we: Based on a sample of 600 people, 5% owned cats The p-value is: Ho≥ 0.1 Ho: ≤0.1 Ho:p> 0.1 H₁:μ 0.1 H₁:p < 0.1 O O Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals)
Test the claim that the mean GPA of night students is larger than 2.6 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p > 0.65 Ho:p 2.6 H1:p 0.65 H1:p+ 0.65 H1:µ > 2.6 H1:µ + 2.6 H:µ < 2.6 %3D The test is: two-tailed right-tailed left-tailed Based on a sample of 65 people, the sample mean GPA was 2.63 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 2.8 at the .10 significance level. The null and alternative hypothesis would be: Ho: p=0.7 Ho: p = 0.7 Ho:μ = 2.8 Ho: H₁:p> 0.7 H₁:p 2.8 H₁: The test is: left-tailed two-tailed right-tailed o The test statistic is: 2.8 Ho:p = 0.7 Ho:μ = 2.8 0 <2.8 H₁:p 0.7 H₁: 2.8 Based on a sample of 40 people, the sample mean GPA was 2.83 with a standard deviation of 0.02 (to 2 decimals) The critical value is: = (to 2 decimals)
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.025 significance level. The null and alternative hypothesis would be: Ho: HN S HD Ho:pN 2 PD Ho:PN = PD Ho:UN = HD Ho: PN HD H:PN PD H1: µN Next Question hp
Women athletes at a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 38 women athletes at the school showed that 23 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%? Use a 10% level of significance. What is the level of significance? (b) State the null and alternate hypotheses. H0: p = 0.67; H1: p > 0.67 H0: p = 0.67; H1: p ≠ 0.67 H0: p < 0.67; H1: p = 0.67 H0: p = 0.67; H1: p < 0.67 What sampling distribution will you use? The Student's t, since np < 5 and nq < 5. The standard normal, since np < 5 and nq < 5. The standard normal, since np > 5 and nq > 5. The Student's t, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) Find the P-value of the test statistic. (Round your answer to four decimal places.)…
Test the claim that the mean GPA of night students is larger than 2.4 at the 0.025 significance level. The null and alternative hypothesis would be: Ho: µ = — 2.4 Но:р 2.4 Н: + 2.4 H:p> 0.6 H:д> 2.4 Hi:p #0.6 Hi:p < 0.6 Н:р < 2.4 The test is: left-tailed two-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.41 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
A hypothesis test on a regression coefficient fails to reject the null hypothesis at the 5% significance level. This means:
Test the claim that the proportion of people who own cats is significantly different than 40% at the 0.2 significance level. The null and alternative hypothesis would be: Ho:p 0.4 Ho: u 2 0.4 Ho:p = 0.4 Ho: p = 0.4 Ho:u 0.4 H1:p 0.4 The test is: two-tailed left-tailed right-tailed Based on a sample of 700 people, 34% owned cats The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: DVideo M hp
Test the claim about the population variance o² at the level of significance α. Assume the population is normally distributed. Claim: o² ≥8.5; α = 0.10 2 Sample statistics: s² = 7.78, n = 25 Write the null and alternative hypotheses. Ho: 0² ≥ 8.5 Ha: 0² < 8.5 (Type integers or decimals. Do not round.) Calculate the standardized test statistic. x² = 21.97 (Round to two decimal places as needed.) Determine the P-value. P-value = (Round to three decimal places as needed.)
Test the daim that the proportion of men who own cats is significan tly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho:PM = PF Ho:HM PF Ho:PM µp H1:µM PF H1:µM + HF The test is left-tailed two-tailed right-tailed Based on a sample of 80 men, 40% owned cats Based on a sample of 20 women, 50% owned cats positive Critical Value = [three decimal accuracy] Test Statistic = [three decimal accuracy] Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the proportion of people who own cats is smaller than 70% at the 0.1 significance level.The alternative hypothesis would be: p<0.7p<0.7 p≠0.7p≠0.7 μ>0.7μ>0.7 μ<0.7μ<0.7 μ≠0.7μ≠0.7 p>0.7p>0.7 The test is: left-tailed right-tailed two-tailed Based on a sample of 600 people, 66% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of people who own cats is larger than 20% at the 0.005 significance level. The null and alternative hypothesis would be: H2:p = 0.2 Họ:p 2 0.2 H9:p 0.2 H9:p = 0.2 Hg: u 0.2 H1: u 0.2 The test is: left-tailed two-tailed right-tailed Based on a sample of 300 people, 24% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

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