Why did it became 4F/A from F/A, in (a) DESIGN PROBLEMS36.Solution:s = axial stresss = shear stress(a)A hook is attached to a plate shown and supports a static load of 12,000 lb. Thematerial is to be AISI C1020, as rolled. (a) Set up strength equations fordimensions d, D, h, and t. Assume that the bending in the plate is negligible.(b) Determine the minimum permissible value of these dimensions. In estimatingthe strength of the nut, let D₁ = 1.2d. (c) Choose standard fractional dimensionswhich you think would be satisfactory.S=F・nd²4FπdRound NutE==CHAHEELCentradace²Problems 36-38.

Answered: S= 1 4 F nd² = 4F πα?

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Mechanical Engineering

S= 1 4 F nd² = 4F πα?

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.2.12P: Solve the preceding problem if the diameter is 480 mm, the pressure is 20 MPa, the yield stress in...

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