RWS-1 Consider a bowling ball which is tossed down a bowling alley. For this problem, we consider the bowling ball to be a uniform sphere of mass M and radius R, with a moment of inertia given by 1=(2/5)MR². The moment the ball hits the ground (t=0), it is moving horizontally with initial linear speed vo, but it is not rotating (mo 0). Due to kinetic friction between the ground and the ball, it begins to rotate as it slides. The coefficient of kinetic friction is ju. As the ball slides along the lane, its angular speed steadily increases. At some point (time te), the "no-slip" condition kicks in, so that o = v/R. After this, the ball moves with a constant linear and angular speed. Solve all parts of this problem symbolically. a) Use Newton's second law to find an expression for the linear acceleration of the ball along the x-direction while the ball is slipping, a. The free body diagram of the ball is shown below. Your final expression should only involve the variables g and u. b) Use the rotational version of Newton's second law to find an expression for the angular acceleration of the ball along the z-direction while the ball is slipping, az. Your final expression should only involve the variables R, g, and uk. c) You should have found that the linear acceleration a. from part a) and the angular acceleration az from part b) are constant. This means that our familiar kinematic equations below will apply while the ball slides down the lane. At time te, the moment the ball begins to roll without slipping, we have oz =-V/R (the negative sign is due to the fact that the ball rotates clockwise, in the -z direction). Use this to find an expression for the time te. Your final expression should only involve the
RWS-1 Consider a bowling ball which is tossed down a bowling alley. For this problem, we consider the bowling ball to be a uniform sphere of mass M and radius R, with a moment of inertia given by 1=(2/5)MR². The moment the ball hits the ground (t=0), it is moving horizontally with initial linear speed vo, but it is not rotating (mo 0). Due to kinetic friction between the ground and the ball, it begins to rotate as it slides. The coefficient of kinetic friction is ju. As the ball slides along the lane, its angular speed steadily increases. At some point (time te), the "no-slip" condition kicks in, so that o = v/R. After this, the ball moves with a constant linear and angular speed. Solve all parts of this problem symbolically. a) Use Newton's second law to find an expression for the linear acceleration of the ball along the x-direction while the ball is slipping, a. The free body diagram of the ball is shown below. Your final expression should only involve the variables g and u. b) Use the rotational version of Newton's second law to find an expression for the angular acceleration of the ball along the z-direction while the ball is slipping, az. Your final expression should only involve the variables R, g, and uk. c) You should have found that the linear acceleration a. from part a) and the angular acceleration az from part b) are constant. This means that our familiar kinematic equations below will apply while the ball slides down the lane. At time te, the moment the ball begins to roll without slipping, we have oz =-V/R (the negative sign is due to the fact that the ball rotates clockwise, in the -z direction). Use this to find an expression for the time te. Your final expression should only involve the
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question

Transcribed Image Text:RWS-1 Consider a bowling ball which is tossed down a bowling alley. For this problem, we will
consider the bowling ball to be a uniform sphere of mass M and radius R, with a moment of
inertia given by I= (2/5)MR2. The moment the ball hits the ground (t 0), it is moving
horizontally with initial linear speed vo, but it is not rotating (oo = 0). Due to kinetic friction
between the ground and the ball, it begins to rotate as it slides. The coefficient of kinetic friction
is uk. As the ball slides along the lane, its angular speed steadily increases. At some point (time
to), the "no-slip" condition kicks in, so that o = v/R. After this, the ball moves with a constant
%3D
%3D
linear and angular speed. Solve all parts of this problem symbolically.
a) Use Newton's second law to find an expression for the linear acceleration of the ball
along the x-direction while the ball is slipping, ax. The free body diagram of the ball
is shown below. Your final expression should only involve the variables g and uk.
b) Use the rotational version of Newton's second law to find an expression for the
angular acceleration of the ball along the z-direction while the ball is slipping, az.
Your final expression should only involve the variables R, g,
c) You should have found that the linear acceleration a from part a) and the angular
acceleration oa, from part b) are constant. This means that our familiar kinematic
equations below will apply while the ball slides down the lane. At time te, the
moment the ball begins to roll without slipping, we have oz =-Vx/R (the negative
sign is due to the fact that the ball rotates clockwise, in the -z direction). Use this to
find an expression for the time te. Your final expression should only involve the
and
Hk.
variables vo, g,
and
V = Vox +at and , = Wo, + a_t
d) Come up with an expression for the linear speed of the ball when no slip condition
kicks in. Simply plug the time te and the linear acceleration ax into the kinematic
equation for vx above. Your final expression should just be a numerical factor
multiplied by vo.
e) The kinetic energy of the ball when it begins to roll without slipping is less than the
initial kinetic energy of the ball (at t 0). This is because kinetic friction acts on the
ball as it slides down the lane, which removes mechanical energy. Come up with an
expression the change in kinetic energy, which only depends on M and vo.
Remember, the ball is a rigid body with both rotational and translational kinetic
energy.
f) Finally, calculate the percentage of the initial kinetic energy that is lost (change in
kinetic energy divided by initial kinetic energy times 100). This will be a just
number, which does not depend on any of the the variables in the problem.
CM
Vo
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you

Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press

Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON

Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education

Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press

Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON

Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education

Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY

Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning

Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY