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A spring is stretched 3 cm by a force of 6 N. Thus, according to Hooke's Law, the spring DO = 200 N. Assume as usual, that r = 0 is the equilibrium position. constant is k 0.03 A mass of 8 kg is now attached to the end of the spring, and it is set in motion with initial position xo = 0 and with initial velocity 10 (m) to the left. ( So, v(0) = -10(m).)

A spring is stretched 3 cm by a force of 6 N. Thus, according to Hooke's Law, the spring DO = 200 N. Assume as usual, that r = 0 is the equilibrium position. constant is k 0.03 A mass of 8 kg is now attached to the end of the spring, and it is set in motion with initial position xo = 0 and with initial velocity 10 (m) to the left. ( So, v(0) = -10(m).)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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A spring is stretched 3 cm by a force of 6 N. Thus, according to Hooke's Law, the spring DO = 200 N. Assume as usual, that r = 0 is the equilibrium position. constant is k 0.03 A mass of 8 kg is now attached to the end of the spring, and it is set in motion with initial position xo = 0 and with initial velocity 10 (m) to the left. ( So, v(0) = -10(m).)
Transcribed Image Text:A spring is stretched 3 cm by a force of 6 N. Thus, according to Hooke's Law, the spring DO = 200 N. Assume as usual, that r = 0 is the equilibrium position. constant is k 0.03 A mass of 8 kg is now attached to the end of the spring, and it is set in motion with initial position xo = 0 and with initial velocity 10 (m) to the left. ( So, v(0) = -10(m).)
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