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Rutherfords scattering
mV₂ = Pf
글
particle
y
10
4
D
r
nudeus.
scattering angle
p=90²-1/2
D= distance of closest approach = 477²0 MV²
b= impact parameter = Cot &
r=distance of x-particle to nuclens
++ (Coup-1)
X
Solve when (+3.4=11-0)
you get (b= £cot £)
explain this phenomenon

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