Run a regression analysis on the following bivariate set of data with y as the response variable.Xy23.868.920.65032.6 69.321.467.521.9 56.617.7 54.428.576.725.964.518.3 52.516.842.229.976Verify that the correlation is significant at an a = 0.05. If the correlation is indeed significant, predictwhat value (on average) for the explanatory variable will give you a value of 56 on the response variable.What is the predicted explanatory value?X =(Report answer accurate to one decimal place.)

Regression analysis can be performed using Excel. Enter the data in the spreadsheet Go to DATA >…

Answered: Run a regression analysis on the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A regression analysis was performed to predict weight (y, in kg) using height (x, in cm) among 150 children. The coefficient of determination was . Which of the following is a valid interpretation? a. For each 1-cm increase in height, weight tends to increase by about 0.32 kg b. There is no association between weight and height c. Height accounts for about 32% of the total variability in weight d. The correlation between weight and height is about 0.32
Here is a bivariate data set. Find the regression equation for the response variable y. x y 60.9 36.2 55.8 44.3 27.8 61.7 36.1 56.3 56 53.7 49.8 55.2 45.7 51.5 60.1 46.6 63.1 50 63.9 40.2 68.8 45.4 32.3 60.4 76.6 40.6 65.4 46 65.6 42.7 regression equation: Enter the equation in slope-intercept form with parameters accurate to three decimal places.
Run a regression analysis on the following bivariate set of data with y as the response variable. x y -9.7 -66.2 5.6 28.3 -4.5 11.9 35.6 94.9 15.7 21.1 30.8 86.3 48.7 127.9 13 57.3 35.3 109 23.6 32.4 58 166.3 28.1 64.4 19.1 51.5 25.6 53.3 46.1 186.4 43.5 128 Predict what value (on average) for the response variable will be obtained from a value of 14.8 as the explanatory variable. Use a significance level of α=0.05 to assess the strength of the linear correlation.What is the predicted response value? y =
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 61.1 78.9 58.6 84.5 70.2 58.1 62.3 65.4 64.2 68.9 58 84.1 63.7 70.2 64.6 71.9 68.3 71.5 61.7 77.5 59.3 77.4 64.6 71.2 Find the correlation coefficient and report it accurate to three decimal places.r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %Based on the data, calculate the regression line (each value to three decimal places)y = x + Predict what value (on average) for the response variable will be obtained from a value of 61.9 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value? (Report answer accurate to one decimal place.)
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 34.4 51.4 21.3 55.8 42.1 45.1 46 44.3 16.6 64 45.5 45.9 41.8 38.8 20.8 56.6 27.6 52.9 12 66.2 35.6 52.4 21.6 57.4 Predict what value (on average) for the response variable will be obtained from a value of 36.9 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value?y = (Report answer accurate to one decimal place.)
Run a regression analysis on the following bivariate set of data with y as the response variable. 58.6 53.6 20 43 24.6 44.1 9.7 40.8 55.1 57.4 -10.3 33.1 39.1 44.9 27.8 48.4 2 33.8 37.6 51.2 52.5 54.3 -12.6 35 Find the correlation coefficient and report it accurate to three decimal places. What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%.you would enter 84.5 without the percent symbol.) 9% Based on the data, calculate the regression line (each value to three decimal places) y = x+ Predict what value (on average) for the response variable will be obtained from a value of 53 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y =
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 59.6 57.3 20.1 61.9 8 87.2 0.1 91.7 31.7 67.6 31.9 62 19.9 74.7 33.1 85.4 0.8 82.8 56.3 59.4 3.7 90.7 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 89.2 on the response variable.What is the predicted explanatory value?x =
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 57.9 -34.4 16.6 92 40.1 89 55.8 54.5 57.9 27.4 17.3 164.1 65.2 62.4 48.3 51.9 66.2 14.5 70.9 -39.2 57 -90.1 58.5 63 Find the correlation coefficient and report it accurate to three decimal places.r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %
Run a regression analysis on the following data set with y as the response variable. y 114 67.1 40.3 87.2 89 91.4 26.5 92.3 9.8 94.9 22.2 88.3 -0.5 What is the predicted value of the response variable when x = 82.5? y= || Round to 1 decimal place. xin
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 60.5 38.5 81.4 13.6 3.5 132.1 52.8 69.8 51.1 30 81.1 11.4 47.1 50 23 119.2 57.9 45.2 58.6 31.8 55.9 98.5 47.6 52 Verify that the correlation is significant at an α=0.05.If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 126.3 on the response variable.What is the predicted explanatory value? x=
Here is a bivariate data set. x y 97.2 41.8 65.7 55.1 62.4 56.8 77.8 53.2 90.9 36.9 63.7 56.8 86.3 43.1 86.6 46.9 85.7 44.4 Find the correlation coefficient and report it accurate to three decimal places.r =
The paired data below consists of heights and weights of 6 randomly selected adults. Find the linear correlation coefficient, the linear regression line, and predict the weight of a randomly selected person who is 1.69 meters tall. X Height (meters) 1.61 1.72 1.78 1.80 1.67 1.88 Y Weight (kg) 54 62 70 84 61 92

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