Rule: Do it with students and not for them Exercise 3 Calculate the change in enthalpy for the reaction of one mole of PbO2 from lead and oxygen at 550°C. Given: 1 Pb+ 02PbO, AH 298 = -219242 J.mol-1 Pb 3PbO + +10 0₂ = Pb304, AH 298 -76986 J.mol-1 PbO Pb304023PbO2, AH 298 -94977 J.mol-1 02 = Cp(Pb) 38.4 + 1.9 × 10-3T Cp(02) 28.6 +1.4 × 10-3T - 8.4 × 105T-2 = Cp(Pb) 76.2 4.6 × 10-³T
Rule: Do it with students and not for them Exercise 3 Calculate the change in enthalpy for the reaction of one mole of PbO2 from lead and oxygen at 550°C. Given: 1 Pb+ 02PbO, AH 298 = -219242 J.mol-1 Pb 3PbO + +10 0₂ = Pb304, AH 298 -76986 J.mol-1 PbO Pb304023PbO2, AH 298 -94977 J.mol-1 02 = Cp(Pb) 38.4 + 1.9 × 10-3T Cp(02) 28.6 +1.4 × 10-3T - 8.4 × 105T-2 = Cp(Pb) 76.2 4.6 × 10-³T
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question

Transcribed Image Text:Rule: Do it with students and not for them
Exercise 3
Calculate the change in enthalpy for the reaction of one mole of PbO2 from lead and
oxygen at 550°C.
Given:
1
Pb+ 02PbO,
AH 298
=
-219242 J.mol-1 Pb
3PbO +
+10
0₂ = Pb304,
AH 298 -76986 J.mol-1 PbO
Pb304023PbO2,
AH 298 -94977 J.mol-1 02
=
Cp(Pb) 38.4 + 1.9 × 10-3T
Cp(02) 28.6 +1.4 × 10-3T - 8.4 × 105T-2
=
Cp(Pb) 76.2 4.6 × 10-³T
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