Using the data in the table below, calculate AH° in kilojoules for the following reactions. Standard Enthalpies of Formation of Typical Substances Substance AN Ou mot-) Substance AN (N mel- Sutistance ANIOU met-) AN ( met-) Substance -187.6 C,H) -84.667 NO 90.37 Agl) AgBrl) -100.4 HBg) -36 CH,OH) -277.63 NO) 33.8 -127.0 -92.30 Cat N,O) 81.57 Aga AIG) 26.6 CaBe) -682.8 9.67 HI) HNO,(0 ('O'N -1669.8 -173.2 CCO) -1207 11 Al,0,0 C) graphite) COg) -811.32 -795.0 Nald HC,H,0,) -635.5 NAHCO,0 Na,CO -110.5 -487.0 CO -947.7 Co) -393.5 Ca(OH),) -986.59 -1131 CHA) -74.848 60.84 CaSO, -1432.7 NaCK -411.0 0. Caso, H,O) - 1575.2 NaOHG) -426.8 CH,a) CHJ) CH,OH(A -82.0 14.2 CaSo, 2H,OG) -2021.1 Na SO,00 -1384.5 -238.6 KC) -435.89 CONHà (urea) CONH KSO Ng) NHẠ -333.19 -1433.7 Fel) -391.2 Fe0,6) -822.2 PbO) -219.2 226.75 52.284 CH) -46.19 -3154 HOp) -241.8 -296.9 D'HN H,On -285.9 so,) -395.2 (a) 2H202() → 2H20(1) + O2(3) (b) HCI(g) + NaOH(s) → NaCI(s) + H20() Part 1 Your Answer Correct Answer (Used) For reaction (a) 2H202() - 2H20) + O23), what is the equation for the change in enthalpy of this reaction? [2AHF(H20(0) + AHf(02(3)) - [2AHF°(H2O2(0)] [2AHf(H202(0)] -[2AHF°(H20() + AHf°(O2(3)] LAHF(02(3)| - [AHP(H2O2M) + AHF°(H2O(0)] (AHP(H202) + AHf (H20(1)) - [AH¢°(02(3)] Part 2 Use the values from the given table and the equation you chose in Part 1 to find the overall change in enthalpy for the reaction, i Save for Later Attempts: 0 of 3 used Submit Answer
Using the data in the table below, calculate AH° in kilojoules for the following reactions. Standard Enthalpies of Formation of Typical Substances Substance AN Ou mot-) Substance AN (N mel- Sutistance ANIOU met-) AN ( met-) Substance -187.6 C,H) -84.667 NO 90.37 Agl) AgBrl) -100.4 HBg) -36 CH,OH) -277.63 NO) 33.8 -127.0 -92.30 Cat N,O) 81.57 Aga AIG) 26.6 CaBe) -682.8 9.67 HI) HNO,(0 ('O'N -1669.8 -173.2 CCO) -1207 11 Al,0,0 C) graphite) COg) -811.32 -795.0 Nald HC,H,0,) -635.5 NAHCO,0 Na,CO -110.5 -487.0 CO -947.7 Co) -393.5 Ca(OH),) -986.59 -1131 CHA) -74.848 60.84 CaSO, -1432.7 NaCK -411.0 0. Caso, H,O) - 1575.2 NaOHG) -426.8 CH,a) CHJ) CH,OH(A -82.0 14.2 CaSo, 2H,OG) -2021.1 Na SO,00 -1384.5 -238.6 KC) -435.89 CONHà (urea) CONH KSO Ng) NHẠ -333.19 -1433.7 Fel) -391.2 Fe0,6) -822.2 PbO) -219.2 226.75 52.284 CH) -46.19 -3154 HOp) -241.8 -296.9 D'HN H,On -285.9 so,) -395.2 (a) 2H202() → 2H20(1) + O2(3) (b) HCI(g) + NaOH(s) → NaCI(s) + H20() Part 1 Your Answer Correct Answer (Used) For reaction (a) 2H202() - 2H20) + O23), what is the equation for the change in enthalpy of this reaction? [2AHF(H20(0) + AHf(02(3)) - [2AHF°(H2O2(0)] [2AHf(H202(0)] -[2AHF°(H20() + AHf°(O2(3)] LAHF(02(3)| - [AHP(H2O2M) + AHF°(H2O(0)] (AHP(H202) + AHf (H20(1)) - [AH¢°(02(3)] Part 2 Use the values from the given table and the equation you chose in Part 1 to find the overall change in enthalpy for the reaction, i Save for Later Attempts: 0 of 3 used Submit Answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Answer pt 2
![Using the data in the table below, calculate AH in kilojoules for the following reactions.
Standard Enthalpies of Formation of Typical Substances
ANI (NI mel-
Sutistance
ANTOU mat-)
90.37
Substance
AN ( met-)
Substance
ANTO mot-)
Substance
NO)
NO
NO()
-187.6
CH.)
-84.667
Agli)
AgBr()
-100.4
HBrg)
-36
CH,OH)
-277.63
33.8
-127.0
-92.30
Cato
81.57
26.6
CaBe)
-682.8
9.67
HI(g)
HNO,(O
AIG)
(Po'N
-1669.8
-173.2
CCO)
-1207
11
Al0,0
C) (graphite)
COlg)
-811.32
-795.0
Nalo
-635.5
NaHCO,)
Na,CO,)
-110.5
HC,H,0,)
-487.0
CO)
--947.7
-393.5
-74.848
Coe)
Hg)
Ca(OH),)
-986.59
-1131
CHA)
Hee)
60.84
-1432.7
NaC
-411.0
Caso, H,O)
- 1575.2
NaOHG)
-426.8
CH,aG)
CHJ)
CH,OH(A
CONH,à (urea)
CONH)
-820
14.2
CasO, ZH,00)
-2021.1
Na SO,)
-1384.5
-238.6
-435.89
Cle)
-333.19
KSO
-1433.7
Fel)
-391.2
FeO,6)
-822.2
PbO)
-219.2
CH)
226.75
-46.19
52.284
So)
so,)
CH)
-3154
HOlg)
-241.8
296.9
D'HN
-285.9
-395.2
(a) 2H2O2(1) → 2H2O(1) + O2l3)
(b) HCI(g) + NaOH(s) → NaCI(s) + H20()
it
Part 1
Your Answer
Correct Answer (Used)
For reaction (a) 2H2O2()
→ 2H20() + O2(g), what is the equation for the change in enthalpy of this reaction?
* [2AHF°(H2O(0) + AHF°(O2(3)) - [2AHf°(H2O2())]
[2AHF"(H202()] -[2AHF°(H2O(1)) + AHf°(O2(3)]
LAHF(02(3))) - [AHP(H2O2M) + AHF°(H2O(0)]
(AHP(H2O2) + AHf(H2O(1)) -[AHF°(02(3)|
Part 2
Use the values from the given table and the equation you chose in Part 1 to find the overall change in enthalpy for
the reaction.
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Transcribed Image Text:Using the data in the table below, calculate AH in kilojoules for the following reactions.
Standard Enthalpies of Formation of Typical Substances
ANI (NI mel-
Sutistance
ANTOU mat-)
90.37
Substance
AN ( met-)
Substance
ANTO mot-)
Substance
NO)
NO
NO()
-187.6
CH.)
-84.667
Agli)
AgBr()
-100.4
HBrg)
-36
CH,OH)
-277.63
33.8
-127.0
-92.30
Cato
81.57
26.6
CaBe)
-682.8
9.67
HI(g)
HNO,(O
AIG)
(Po'N
-1669.8
-173.2
CCO)
-1207
11
Al0,0
C) (graphite)
COlg)
-811.32
-795.0
Nalo
-635.5
NaHCO,)
Na,CO,)
-110.5
HC,H,0,)
-487.0
CO)
--947.7
-393.5
-74.848
Coe)
Hg)
Ca(OH),)
-986.59
-1131
CHA)
Hee)
60.84
-1432.7
NaC
-411.0
Caso, H,O)
- 1575.2
NaOHG)
-426.8
CH,aG)
CHJ)
CH,OH(A
CONH,à (urea)
CONH)
-820
14.2
CasO, ZH,00)
-2021.1
Na SO,)
-1384.5
-238.6
-435.89
Cle)
-333.19
KSO
-1433.7
Fel)
-391.2
FeO,6)
-822.2
PbO)
-219.2
CH)
226.75
-46.19
52.284
So)
so,)
CH)
-3154
HOlg)
-241.8
296.9
D'HN
-285.9
-395.2
(a) 2H2O2(1) → 2H2O(1) + O2l3)
(b) HCI(g) + NaOH(s) → NaCI(s) + H20()
it
Part 1
Your Answer
Correct Answer (Used)
For reaction (a) 2H2O2()
→ 2H20() + O2(g), what is the equation for the change in enthalpy of this reaction?
* [2AHF°(H2O(0) + AHF°(O2(3)) - [2AHf°(H2O2())]
[2AHF"(H202()] -[2AHF°(H2O(1)) + AHf°(O2(3)]
LAHF(02(3))) - [AHP(H2O2M) + AHF°(H2O(0)]
(AHP(H2O2) + AHf(H2O(1)) -[AHF°(02(3)|
Part 2
Use the values from the given table and the equation you chose in Part 1 to find the overall change in enthalpy for
the reaction.
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