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RT a QT, then APTQ a ASTR by what c. SAA d. SSS ch other at point T, and PO RS. Which postulate/theorem can prove c. A & B d. None of the Above a of the following is FALSE? c. PQ a RS

RT a QT, then APTQ a ASTR by what c. SAA d. SSS ch other at point T, and PO RS. Which postulate/theorem can prove c. A & B d. None of the Above a of the following is FALSE? c. PQ a RS

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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answer just 14 and 15 pls
For items 11 to 15, consider the figure at the right. 11. If T bisects R & PS, then APTQ ASTR by what postulate/theorem? a. ASA b. SAS c. SAA d. SSS 12. If 20 = 2R, and RT a QT, then APTQ a ASTR by what postulate/theorem? a. ASA b. SAS R4 c. SAA d. SSS 13. RQ and PS bisect each other at point T, and PO = RS. Which postulate/theorem can prove that APTQ 2 ASTR? a. SSS b. SAS 14. If APTQ = ASTR, which of the following is FALSE? a. PT a TS b. ZP a LS 15. If APTQ = ASTR, then ZR = Q by what reason? a. Vertical angles are congruent b. CPCTC c. A & B d. None of the Above c. PO a RS d. ER = LS c. Opposite angles are congruent d. None of the above
Transcribed Image Text:For items 11 to 15, consider the figure at the right. 11. If T bisects R & PS, then APTQ ASTR by what postulate/theorem? a. ASA b. SAS c. SAA d. SSS 12. If 20 = 2R, and RT a QT, then APTQ a ASTR by what postulate/theorem? a. ASA b. SAS R4 c. SAA d. SSS 13. RQ and PS bisect each other at point T, and PO = RS. Which postulate/theorem can prove that APTQ 2 ASTR? a. SSS b. SAS 14. If APTQ = ASTR, which of the following is FALSE? a. PT a TS b. ZP a LS 15. If APTQ = ASTR, then ZR = Q by what reason? a. Vertical angles are congruent b. CPCTC c. A & B d. None of the Above c. PO a RS d. ER = LS c. Opposite angles are congruent d. None of the above
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