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4. Given the quadratic y = (x + 2)2 - 1, answer the questions and sketch the C a) The b) The vertex is: (-2, -1) c) The axis of symmetry is x = -2 Solve for the y-intercept (sub x = 0 into equation). Y-intercept is 3 Y=(x²) -1 = 6 + 2)² - 1 =4-1 =3

4. Given the quadratic y = (x + 2)2 - 1, answer the questions and sketch the C a) The b) The vertex is: (-2, -1) c) The axis of symmetry is x = -2 Solve for the y-intercept (sub x = 0 into equation). Y-intercept is 3 Y=(x²) -1 = 6 + 2)² - 1 =4-1 =3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4. Given the quadratic y = (x + 2)² - 1, answer the questions and sketch the graph using the points. a) The vertex is: (-2,-1) b) c) The axis of symmetry is x = -2 Solve for the y-intercept (sub x = 0 into equation). Y-intercept is Y = (x²) - 1 = 6 + 2)² -1 =4-1 = 3 d) The point symmetrical to the y-intercept is: e) The first step is: f) Sketch the graph using these 5 points. -6 1. -4 Ay 10- -2 8 6- 4 2- -2- -4- -6- 2 4 6
Transcribed Image Text:4. Given the quadratic y = (x + 2)² - 1, answer the questions and sketch the graph using the points. a) The vertex is: (-2,-1) b) c) The axis of symmetry is x = -2 Solve for the y-intercept (sub x = 0 into equation). Y-intercept is Y = (x²) - 1 = 6 + 2)² -1 =4-1 = 3 d) The point symmetrical to the y-intercept is: e) The first step is: f) Sketch the graph using these 5 points. -6 1. -4 Ay 10- -2 8 6- 4 2- -2- -4- -6- 2 4 6
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