Review Quiz III Name: is ultin Lab Section: 1. (4.0 points) Rank the following in order of increasing boiling points by considering the most important intermolecular forces and give your reason: NH3, H₂O, Ne, and CO 2. (4.0 points) A beaker contains 350.0 g of warm water at 98.0 °C. A piece of metal at 5.90 °C is placed in the beaker. The final temperature of the system reaches 67.0 °C. Determine the mass of the metal if its specific heat is 0.298 J/g °C. The specific heat of water is 4.184 J/g °C. m. 0.29465192.61. E-350g - 4.184 513-31°C m. 18,20785= 45396.4 I 1420787 18.20785 m=2493, 24, Ch 3. (4.0 points) Without any detailed calculation consider the following equations and predict the sign of AS. a. N2(g) + 3H2 (g) → 2NH3 (g) b. 2H2(g) + O2 (g) → 2H2O (1) c. CH4 (g) +202 (g) → CO2 (g) + 2H2O (1) d. 2N2 (g) +502 (g) → 2N20s (g)

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Review Quiz III
Name: is ultin
Lab Section:
1. (4.0 points) Rank the following in order of increasing boiling points by considering the
most important intermolecular forces and give your reason:
NH3, H₂O, Ne, and CO
2. (4.0 points) A beaker contains 350.0 g of warm water at 98.0 °C. A piece of metal at 5.90
°C is placed in the beaker. The final temperature of the system reaches 67.0 °C.
Determine the mass of the metal if its specific heat is 0.298 J/g °C. The specific heat of
water is 4.184 J/g °C.
m. 0.29465192.61. E-350g - 4.184 513-31°C
m. 18,20785= 45396.4 I
1420787
18.20785
m=2493, 24,
Ch
3. (4.0 points) Without any detailed calculation consider the following equations and
predict the sign of AS.
a. N2(g) + 3H2 (g) → 2NH3 (g)
b. 2H2(g) + O2 (g) → 2H2O (1)
c. CH4 (g) +202 (g) → CO2 (g) + 2H2O (1)
d. 2N2 (g) +502 (g) → 2N20s (g)
Transcribed Image Text:Review Quiz III Name: is ultin Lab Section: 1. (4.0 points) Rank the following in order of increasing boiling points by considering the most important intermolecular forces and give your reason: NH3, H₂O, Ne, and CO 2. (4.0 points) A beaker contains 350.0 g of warm water at 98.0 °C. A piece of metal at 5.90 °C is placed in the beaker. The final temperature of the system reaches 67.0 °C. Determine the mass of the metal if its specific heat is 0.298 J/g °C. The specific heat of water is 4.184 J/g °C. m. 0.29465192.61. E-350g - 4.184 513-31°C m. 18,20785= 45396.4 I 1420787 18.20785 m=2493, 24, Ch 3. (4.0 points) Without any detailed calculation consider the following equations and predict the sign of AS. a. N2(g) + 3H2 (g) → 2NH3 (g) b. 2H2(g) + O2 (g) → 2H2O (1) c. CH4 (g) +202 (g) → CO2 (g) + 2H2O (1) d. 2N2 (g) +502 (g) → 2N20s (g)
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