The image displays an assignment from a chemistry homework portal concerning thermochemistry, specifically calculating the heat evolved or absorbed in chemical reactions.**Item 14:****Question:** How much heat in kilojoules is evolved or absorbed in each of the following reactions?**Part A:**- **Reaction:** Burning of 15.5 g of propane.- **Chemical Equation:** \( \text{C}_3\text{H}_8(g) + 5 \text{O}_2(g) \rightarrow 3 \text{CO}_2(g) + 4 \text{H}_2\text{O}(l) \)- **Enthalpy Change (\( \Delta H^\circ \)):** \(-2220 \text{ kJ}\)- **Description:** The task requires calculating the kJ of heat evolved during this exothermic reaction when burning 15.5 g of propane.**Part B:**- **Reaction:** Reaction of 4.88 g of barium hydroxide octahydrate with ammonium chloride.- **Chemical Equation:** \[ \text{Ba}(\text{OH})_2 \cdot 8 \text{H}_2\text{O}(s) + 2 \text{NH}_4\text{Cl}(s) \rightarrow \text{BaCl}_2(aq) + 2 \text{NH}_3(aq) + 10 \text{H}_2\text{O}(l) \]- **Enthalpy Change (\( \Delta H^\circ \)):** \( +80.3 \text{ kJ} \)- **Description:** The task requires calculating the kJ of heat absorbed during this endothermic reaction when reacting 4.88 g of barium hydroxide octahydrate.In both parts, students are prompted to submit their calculated answers by entering them into the answer fields provided below each reaction description.

Given mass of propane = 15.5 g Molar mass of propane = 44 g/mol Number of moles of propane = 15.5/44 = 0.35 mol Amount of heat released per mole of combustion of propane = 2220 KJ Amount of heat released for the combustion of 0.35 mol of propane = 2220 × 0.35 = 777 KJ Given mass of barium hydroxide octahydrate = 4.88 g Molar mass of barium hydroxide octahydrate = 315 g/mol Number of moles of barium hydroxide octahydrate = 4.88/315 = 0.0155 mol Amount of heat absorbed per mole of barium hydroxide octahydrate = 80.3 KJ Amount of heat absorbed for the reaction of 0.0155 mol of barium hydroxide octahydrate = 80.3 × 0.0155 = 1.245 KJ

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Chemistry

Review I Constants Part A Burning of 15.5 g of propane: C,H, (9) + 502(9)→3 CO2(9) + 4 H20(1) AH° =-2220 kJ 阳AE中 ? kJ of heat is evolved Submit Request Answer Part B Reaction of 4.88 g of barium hydroxide octahydrate with ammonium chloride: Ba(OH), 8 H20(s) + 2 NH,CI(s)→BaCl2(aq) + 2 NH3 (ag) + 10 H20(1) AH = +80.3 kJ 同]? kJ of heat is absorbed Submit Request Answer

Review I Constants Part A Burning of 15.5 g of propane: C,H, (9) + 502(9)→3 CO2(9) + 4 H20(1) AH° =-2220 kJ 阳AE中 ? kJ of heat is evolved Submit Request Answer Part B Reaction of 4.88 g of barium hydroxide octahydrate with ammonium chloride: Ba(OH), 8 H20(s) + 2 NH,CI(s)→BaCl2(aq) + 2 NH3 (ag) + 10 H20(1) AH = +80.3 kJ 同]? kJ of heat is absorbed Submit Request Answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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