Calculate the enthalpy of the reaction 4B(s) + 302(9)→2B2O3(s) given the following pertinent information: A. B2O3(s) +3H20(9)→302(g) +B2H6(9), A:H¿ = +2035 kJ mol- B. 2B(s) + 3H2(9)→B2H«(9), c. H2 (9) + ÷O2(9)→H2O(1), D. H20(1)¬H2O(g), 4,H = +36 kJ mol A,H¿ = -285 kJ mol AH§ =+44 kJ mol-1 %3D Express your answer with the appropriate units. • View Available Hint(s) ? A‚H° = Value Units

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part B
Calculate the enthalpy of the reaction
4B(s) + 302(9)→2B2O3(s)
given the following pertinent information:
A. B2O3 (s) + 3H20(g)→302 (g) +BH6(g), A:H = +2035 kJ mol1
B. 2B(s) + 3H2(g)¬B2H6(9),
c. H2 (9) + O2(9)→H2O(1),
D. H2O(1)¬H2O(g),
A,H§ = +36 kJ mol-
A,H = -285 kJ mol 1
A;H§ = +44 kJ mol
Express your answer with the appropriate units.
• View Available Hint(s)
HA
A;H° =
Value
Units
Transcribed Image Text:Part B Calculate the enthalpy of the reaction 4B(s) + 302(9)→2B2O3(s) given the following pertinent information: A. B2O3 (s) + 3H20(g)→302 (g) +BH6(g), A:H = +2035 kJ mol1 B. 2B(s) + 3H2(g)¬B2H6(9), c. H2 (9) + O2(9)→H2O(1), D. H2O(1)¬H2O(g), A,H§ = +36 kJ mol- A,H = -285 kJ mol 1 A;H§ = +44 kJ mol Express your answer with the appropriate units. • View Available Hint(s) HA A;H° = Value Units
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