Return2 pointsBelow is adeveloped TLC plate (1:1 hexanesethyl acetate). The four standards in the tab, acetaminochen, anpirin, caffeine, and ibuprofen are spotted from fet to right.a) Which of the four molecules is most polar based on the TLCExplain how you know in your own wordsb) One of the four standards is impure - which is it? Explain your answer.48

Answered: Image /qna-images/answer/54093111-cacc-4ed7-a751-5c611364cc62.jpg

Return 2pnts Below is a developed TLC plate (1:1 hexanes ethyl acetatel. The four standards in the lah acetaminochen apirin caffeeand buprofen are spotted from left to right al Which of the four molecules is most polar based on the TLCExplain how youknow in your own words b One of the four standards is impure - which is it? Exglain your answer.

Return 2pnts Below is a developed TLC plate (1:1 hexanes ethyl acetatel. The four standards in the lah acetaminochen apirin caffeeand buprofen are spotted from left to right al Which of the four molecules is most polar based on the TLCExplain how youknow in your own words b One of the four standards is impure - which is it? Exglain your answer.

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter6: Solutions And Colloids

Section: Chapter Questions

Problem 6.23P: 6-23 We dissolved 0.32 g of aspartic acid in 115.0 mL of water and obtained a clear solution. After...

See similar textbooks

Similar questions

Separate a mixture of Vitamin D and Vitamin B2 (riboflavin) by paper chromatography. The stationary phase is methanol (CH;OH) and the mobile phase is pentane (C;H12). Place the vitamins in order of elution. Explain why using IMF. (Circle polar sites on each molecule and label all 4 molecules as polar or non-polar.) Vitamin B2 ö: డ H3C NH H;C CH3 CH3 CH3 H3C He H3C HO .. He CH2 Vitamin D He CH2OH HO
For part B, it is not 4.98 x 10-41. I put it in and it was wrong. It is looking for P1.
Separate a mixture of Vitamin D and Vitamin B2 (riboflavin) by paper chromatography. The stationary phase is methanol (CH;OH) and the mobile phase is pentane (C3H12). Place the vitamins in order of elution. Explain why using IMF. (Circle polar sites on each molecule and label all 4 molecules as polar or non-polar.) Vitamin B2 H,C. H;C CH3 NH CH, CH3 H,C H- H3C HO- CH2 He Vitamin D He HO CH2OH :애: :애: :애:
5. Can you explain why not all CuSO4 solution concentrations can be determined from spectrophotometer readings using wavelength absorption at 700 nm? Are there readings that are inaccurate? If not, why not, and if yes, why?
The green band consisted of chlorophylls. What does it tell you about the relative polarity of the chlorophylls ( compared to the carotenoids, the yellow band) that they would only move through the column after switching from a 90:10 mixture of hexane:acetone to only acetone.
Separate a mixture of Vitamin D and Vitamin B2 (riboflavin) by paper chromatography. The stationary phase is methanol (CH;OH) and the mobile phase is pentane (C;H12). Place the vitamins in order of elution. Explain why using IMF. (Circle polar sites on each molecule and label all 4 molecules as polar or non-polar.) Vitamin Ba 0: H3C NH H3C CH3 CH3 CH3 H3C He H3C HO CH2 Vitamin D He CH2OH HO
1. The mobile phase in the TLC simulator uses a mixture of the organic compounds: ethyl acetate and hexane. For each compound: circle the polar and nonpolar regions of the molecule, then label each region with the type of attractive force it could use to interact with neighboring molecules. ethyl acetate H :0: Η Η +4 Η H- H Η hexane H- Η Η Η Η Η Η C -C-H H H H H H H
i) Br 3 H3C, .../IC/ CH3 CH3S Acetone CH₂CH₂OH heat ion between
The Ka for HC2H3O2 is 1.8 x 10-5. What is the value of Kb for C2H3O2?
Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72
Please don't provide handwritten solution ....
diantilis ether. find the peaks