Type 3. If Rc = 0.145 for A₂ + 2B = 2AB(9)(9)Ка=ㅗ4AB 2A2+4B(g)Kc₂=Ког[AB]²[A₂][B]= 0.145[A₂]²[B]*[AB]+دو)ㅗ1 = (k~₁) ²когк сч=?=[AB]² ([AB]² 12[A₂][B]² [[A₂][B] ²=47,56Kc2 = (Kc₁) ² (0.145)=☆ What is Kc3 = ? — Az (g) + B (g) = AB (g)

Kc1 = 0.145For kc3,1/2 A2 (g) + B (g) <=> AB (g) (g) + B (g) <=> AB (g)

Туре 3. IF Kc=0.145 for Az+2B = 2AB (9) (д) давзгаг+48 кс2=? (9) Ка S Ксг I Ког [ABJ2 [Az][в]г = (д) L ког (до = 0.145 [Az] 2 [в]+ гавза Савр [AB]² CA2][B]2 [Az][B]2/ (ка) 2 2 =47.56 I Ксч= (ка) (0.145) Awhat is Каз=? =Az (92+B(9)= авід)

Туре 3. IF Kc=0.145 for Az+2B = 2AB (9) (д) давзгаг+48 кс2=? (9) Ка S Ксг I Ког [ABJ2 [Az][в]г = (д) L ког (до = 0.145 [Az] 2 [в]+ гавза Савр [AB]² CA2][B]2 [Az][B]2/ (ка) 2 2 =47.56 I Ксч= (ка) (0.145) Awhat is Каз=? =Az (92+B(9)= авід)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

Type 3. If Rc = 0.145 for A₂ + 2B = 2AB
(9)
(9)
Ка
=
ㅗ
4AB 2A2+4B
(g)
Kc₂=
Ког
[AB]²
[A₂][B]
= 0.145
[A₂]²[B]*
[AB]+
دو)
ㅗ
1 = (k~₁) ²
ког
к сч=?
=[AB]² ([AB]² 12
[A₂][B]² [[A₂][B] ²
=47,56
Kc2 = (Kc₁) ² (0.145)
=
☆ What is Kc3 = ? — Az (g) + B (g) = AB (g)

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