Resultant field current is OB- 26.5 + 14.5 + 2x 26.5x14.4 cos 53°8 = 37.2 A An 11-kV, 1000-kVA, 3-phase, Y-connecied alternator has a resistance of 2 Q per phase. The open-circuit and full-load zero power factor characteristics are given below. Find the voltage regulation of the alternator for full load current at 0.8 pf. lagging by Potier method. E= 3750 V (90+ IX = 450 V B 37.2 A V = 3465V (90+ 26.5 A Fig. 37.59 Fig. 37.60 It is found 40A Field is s necessany to civculaute short-cbmemit load current current circulate fll using zs me theed to find VRY. using nmf methol tofined UR Field current (A) O.C.C. line voltage Line volts zeropf. 40 50 110 5,800 140 180 7,000 1500 12,500 13,750 10,500 ->0 15,000 8500 12,500 (Calcutta Univ. 1987 and S. Ramanandtirtha Univ. Nanded, 2001)

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Resultant field current is OB- 26.5 + 14.5 +2x26.5x14.4 cos 53°8' =37.2 A
An 11-kV,
1000-kVA, 3-phase, Y-cопneстеd
alternator has a resistance of 2 Q per
phase. The open-circuit and full-load
zero power factor characteristics are
given below. Find the voltage
regulation of the alternator for full
load current at 0.8 pf. lagging by
E= 3750 V
(90+
IX
= 450 V
37.2 A
V = 3465V
(90+
A I
26.5 A
Potier method.
Fig. 37.59
Fig. 37.60
It is found Y0A Field
is vs necessany to circulate short-ctbeemit
load current
current
circulate
fll
@ VRY
using zs me theed to find
.
2.
using nmf methad
tofind UR
Field current (A)
O.C.C. line voltage
Line volts zero pf.
40
50
110
5,800
7,000
140
180
12,500
13,750
10,500
1500
15,000
8500
12,500
(Calcutta Univ. 1987 and S. Ramanandtirtha Univ. Nanded, 2001)
Transcribed Image Text:Resultant field current is OB- 26.5 + 14.5 +2x26.5x14.4 cos 53°8' =37.2 A An 11-kV, 1000-kVA, 3-phase, Y-cопneстеd alternator has a resistance of 2 Q per phase. The open-circuit and full-load zero power factor characteristics are given below. Find the voltage regulation of the alternator for full load current at 0.8 pf. lagging by E= 3750 V (90+ IX = 450 V 37.2 A V = 3465V (90+ A I 26.5 A Potier method. Fig. 37.59 Fig. 37.60 It is found Y0A Field is vs necessany to circulate short-ctbeemit load current current circulate fll @ VRY using zs me theed to find . 2. using nmf methad tofind UR Field current (A) O.C.C. line voltage Line volts zero pf. 40 50 110 5,800 7,000 140 180 12,500 13,750 10,500 1500 15,000 8500 12,500 (Calcutta Univ. 1987 and S. Ramanandtirtha Univ. Nanded, 2001)
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