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Resolve the #2 illustrative problem using the equations for a parabola. (y=Ax²+Bx+C)

Resolve the #2 illustrative problem using the equations for a parabola. (y=Ax²+Bx+C)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Resolve the #2 illustrative problem using the equations for a parabola. (y=Ax²+Bx+C) Note: Your solution should not include the use of the grade diagram for the required. (#1a & #1b, & #2)
2. A grade line Al having a sape of 55 intersect anofther grade ine BC having a skope of -3% at 8. The elevations of points A. B and Core 95 m 100 m ond 97 m respectively. Determine the elevation of the summit of the 100 m poratolic vertical curve to connect the grade ines.
Transcribed Image Text:2. A grade line Al having a sape of 55 intersect anofther grade ine BC having a skope of -3% at 8. The elevations of points A. B and Core 95 m 100 m ond 97 m respectively. Determine the elevation of the summit of the 100 m poratolic vertical curve to connect the grade ines.
Horizontal distance between A and B- (100 - 95)/0.05 = 100 m Horizontal distance between B and C= (100 - 97)/0.03 = 100 m 50 m 50 m 50 m 50 m B (Elev. 100 m) - PT 3% O PC +5%- CE. 97) 0.03 ACElev, 95) 0.05 0.03 St Grade Diagram Su The figure above placed the parabolie curve at the middle-half: Elev PC - Elev A+ 50(0.05) Elev PC- D5 + 2.5 Elev PC - 07.6 m Distance from PC to the summit: 100 0.05 S,= 02.5 0.08 Elevation of the summit: Elevation of the summit Elev PC+s,(0.05) Elevation of the aummit 97.6 +(62.5)(0.05) Elevation of the summit- 90.0625 m
Transcribed Image Text:Horizontal distance between A and B- (100 - 95)/0.05 = 100 m Horizontal distance between B and C= (100 - 97)/0.03 = 100 m 50 m 50 m 50 m 50 m B (Elev. 100 m) - PT 3% O PC +5%- CE. 97) 0.03 ACElev, 95) 0.05 0.03 St Grade Diagram Su The figure above placed the parabolie curve at the middle-half: Elev PC - Elev A+ 50(0.05) Elev PC- D5 + 2.5 Elev PC - 07.6 m Distance from PC to the summit: 100 0.05 S,= 02.5 0.08 Elevation of the summit: Elevation of the summit Elev PC+s,(0.05) Elevation of the aummit 97.6 +(62.5)(0.05) Elevation of the summit- 90.0625 m
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