Resolve the #2 illustrative problem using the equations for a parabola. (y=Ax²+Bx+C)
Resolve the #2 illustrative problem using the equations for a parabola. (y=Ax²+Bx+C)
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter15: Slope Stability
Section: Chapter Questions
Problem 15.14P
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Resolve the #2 illustrative problem using the equations for a parabola. (y=Ax²+Bx+C)
Note: Your solution should not include the use of the grade diagram for the required. (#1a & #1b, & #2)
![2. A grade line Al having a sape of 55 intersect anofther grade ine BC having a
skope of -3% at 8. The elevations of points A. B and Core 95 m 100 m ond 97 m
respectively. Determine the elevation of the summit of the 100 m poratolic vertical
curve to connect the grade ines.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fecb829b6-b2aa-40fe-9720-32dc76a797db%2F0ee7a654-7f38-44f1-a7f7-39d32a34ffae%2F62npm35_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. A grade line Al having a sape of 55 intersect anofther grade ine BC having a
skope of -3% at 8. The elevations of points A. B and Core 95 m 100 m ond 97 m
respectively. Determine the elevation of the summit of the 100 m poratolic vertical
curve to connect the grade ines.
![Horizontal distance between A and B- (100 - 95)/0.05 = 100 m
Horizontal distance between B and C= (100 - 97)/0.03 = 100 m
50 m
50 m
50 m
50 m
B (Elev. 100 m) -
PT
3%
O
PC
+5%-
CE. 97)
0.03
ACElev, 95) 0.05
0.03
St
Grade Diagram
Su
The figure above placed the parabolie curve at the middle-half:
Elev PC - Elev A+ 50(0.05)
Elev PC- D5 + 2.5
Elev PC - 07.6 m
Distance from PC to the summit:
100
0.05
S,= 02.5
0.08
Elevation of the summit:
Elevation of the summit Elev PC+s,(0.05)
Elevation of the aummit 97.6 +(62.5)(0.05)
Elevation of the summit- 90.0625 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fecb829b6-b2aa-40fe-9720-32dc76a797db%2F0ee7a654-7f38-44f1-a7f7-39d32a34ffae%2F89zqb706_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Horizontal distance between A and B- (100 - 95)/0.05 = 100 m
Horizontal distance between B and C= (100 - 97)/0.03 = 100 m
50 m
50 m
50 m
50 m
B (Elev. 100 m) -
PT
3%
O
PC
+5%-
CE. 97)
0.03
ACElev, 95) 0.05
0.03
St
Grade Diagram
Su
The figure above placed the parabolie curve at the middle-half:
Elev PC - Elev A+ 50(0.05)
Elev PC- D5 + 2.5
Elev PC - 07.6 m
Distance from PC to the summit:
100
0.05
S,= 02.5
0.08
Elevation of the summit:
Elevation of the summit Elev PC+s,(0.05)
Elevation of the aummit 97.6 +(62.5)(0.05)
Elevation of the summit- 90.0625 m
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