Using virtual work, compute the vertical displacement at point C of the beam shown below. E = 29(10³) ksi, I = 200 in. 10 kips A 4 ft B A 4 ft C 4 ft D 60 4 ft 10 kips E

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Chapter2: Loads On Structures
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Question 5
Using virtual work, compute the vertical displacement at point C of the beam shown below. E = 29(10³)
ksi, I = 200 in¹.
10 kips
A
4 ft
B
www
4 ft
C
4 ft
D
65
4 ft
10 kips
E
Transcribed Image Text:Question 5 Using virtual work, compute the vertical displacement at point C of the beam shown below. E = 29(10³) ksi, I = 200 in¹. 10 kips A 4 ft B www 4 ft C 4 ft D 65 4 ft 10 kips E
Table for:
Rectangle
M
M
Triangle
M
M
L
Triangle
M
L
Triangle
L
Trapezoid
-6-
slope-0
L
Parabola
slope - 0
L
Parabola
slope-0
S'MQdx
L
Parabola
L
Parabola
M
M
M,
M
M
slope - 0
Q
Rectangle
L
LMQ
LMQ
The values in the table represent the integration of the
product of the two shapes with a common length L.
Triangle
Triangle
Trapezoid Q
LMQ
LMQ
2LMQ
2LMQ
LMQ
LMQ
L
LMQ
LMQ
LMQ
6
MQ (L + a)
SLMQ
(M+M) (M+2M) (2M, + M)
LMQ
0 0
LMQ
LMQ
L
LMQ
LMQ
6
WE
MO(L + b)
LMQ
LMQ
12
L
LMQ
LM(Q+Q)
IM(Q+20)
LM (2Q+Q)
[Q(+b)
+Q(l+a)]
Q(2M,+ M)
+Q (M, + 2M)]
SLMQ [2(sQ+3Q)
(3Q+5Q)
(Q+30)
M3Q+Q)
Transcribed Image Text:Table for: Rectangle M M Triangle M M L Triangle M L Triangle L Trapezoid -6- slope-0 L Parabola slope - 0 L Parabola slope-0 S'MQdx L Parabola L Parabola M M M, M M slope - 0 Q Rectangle L LMQ LMQ The values in the table represent the integration of the product of the two shapes with a common length L. Triangle Triangle Trapezoid Q LMQ LMQ 2LMQ 2LMQ LMQ LMQ L LMQ LMQ LMQ 6 MQ (L + a) SLMQ (M+M) (M+2M) (2M, + M) LMQ 0 0 LMQ LMQ L LMQ LMQ 6 WE MO(L + b) LMQ LMQ 12 L LMQ LM(Q+Q) IM(Q+20) LM (2Q+Q) [Q(+b) +Q(l+a)] Q(2M,+ M) +Q (M, + 2M)] SLMQ [2(sQ+3Q) (3Q+5Q) (Q+30) M3Q+Q)
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