Question 4 Consider the truss shown below. Determine the horizontal displacement of joint C if member CD is 10 mm shorter than intended and member CB is 10 mm longer than intended. (Hint: Refer to Lecture 3_PartIII for the topic and a similar example) 3 m B 3 m A D 8 m A E
Question 4 Consider the truss shown below. Determine the horizontal displacement of joint C if member CD is 10 mm shorter than intended and member CB is 10 mm longer than intended. (Hint: Refer to Lecture 3_PartIII for the topic and a similar example) 3 m B 3 m A D 8 m A E
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Question 4
Consider the truss shown below. Determine the horizontal displacement of joint C if member CD is 10 mm
shorter than intended and member CB is 10 mm longer than intended. (Hint: Refer to Lecture 3_PartIII for
the topic and a similar example)
3 m
B
3 m
A
D
8 m
E
![Table for:
Rectangle
M
M
Triangle
M
M
L
Triangle
M
L
Triangle
L
Trapezoid
-6-
slope-0
L
Parabola
slope - 0
L
Parabola
slope-0
S'MQdx
L
Parabola
L
Parabola
M
M
M,
M
M
slope - 0
Q
Rectangle
L
LMQ
LMQ
The values in the table represent the integration of the
product of the two shapes with a common length L.
Triangle
Triangle
Trapezoid Q
LMQ
LMQ
2LMQ
2LMQ
LMQ
LMQ
L
LMQ
LMQ
LMQ
6
MQ (L + a)
SLMQ
(M+M) (M+2M) (2M, + M)
LMQ
0 0
LMQ
LMQ
L
LMQ
LMQ
6
WE
MO(L + b)
LMQ
LMQ
12
L
LMQ
LM(Q+Q)
IM(Q+20)
LM (2Q+Q)
[Q(+b)
+Q(l+a)]
Q(2M,+ M)
+Q (M, + 2M)]
SLMQ [2(sQ+3Q)
(3Q+5Q)
(Q+30)
M3Q+Q)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F95aeff90-eae1-41d1-a6d5-24c543733ee7%2F982dcc0d-620d-48fa-bf9a-57ecf965ad0b%2Fr7wth4a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Table for:
Rectangle
M
M
Triangle
M
M
L
Triangle
M
L
Triangle
L
Trapezoid
-6-
slope-0
L
Parabola
slope - 0
L
Parabola
slope-0
S'MQdx
L
Parabola
L
Parabola
M
M
M,
M
M
slope - 0
Q
Rectangle
L
LMQ
LMQ
The values in the table represent the integration of the
product of the two shapes with a common length L.
Triangle
Triangle
Trapezoid Q
LMQ
LMQ
2LMQ
2LMQ
LMQ
LMQ
L
LMQ
LMQ
LMQ
6
MQ (L + a)
SLMQ
(M+M) (M+2M) (2M, + M)
LMQ
0 0
LMQ
LMQ
L
LMQ
LMQ
6
WE
MO(L + b)
LMQ
LMQ
12
L
LMQ
LM(Q+Q)
IM(Q+20)
LM (2Q+Q)
[Q(+b)
+Q(l+a)]
Q(2M,+ M)
+Q (M, + 2M)]
SLMQ [2(sQ+3Q)
(3Q+5Q)
(Q+30)
M3Q+Q)
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